Submission #875187

#	Time	Username	Problem	Language	Result	Execution time	Memory
875187		Dr_rabi3	Klasika (COCI20_klasika)	C++14	110 / 110	1875 ms	455452 KiB

klasika

/***   Coding for Fun ^^ وَمَا تَوْفِيقِي إِلَّا بِاللَّهِ ۚ عَلَيْهِ تَوَكَّلْتُ وَإِلَيْهِ أُنِيبُ    ***/
#pragma GCC optimize ("O3")
#pragma GCC optimize ("unroll-loops")
#include <bits/stdc++.h>
#include <ext/numeric>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define ll long long
#define ull unsigned ll
#define ld long double
#define ed '\n'
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define fixed(x) fixed<<setprecision(x)
#define memo(dp,x) memset(dp,x,sizeof(dp))
#define sumOf(a) (ll)((-1 + sqrt(8LL * a + 1)) / 2)
#define debug cerr
#define Good_Bay return

using namespace std;
using namespace __gnu_pbds;
std::mt19937_64 rng(std::chrono::system_clock::now().time_since_epoch().count());

template < typename T > using ordered_set = tree< T, null_type, less_equal< T >, rb_tree_tag, tree_order_statistics_node_update >;

template < typename T > istream& operator >> (istream& in, vector < T >& v) {
    for (auto& x : v) in >> x;
    return in;
}

template < typename T > ostream& operator << (ostream& out, const vector < T >& v) {
    for (const T& x : v) out << x << ' ';
    return out;
}


void Accept() { // for VS code
    ios_base::sync_with_stdio(false);
    cout.tie(nullptr);
    cin.tie(nullptr);
    // #ifndef ONLINE_JUDGE
    // freopen("input.txt", "r", stdin);
    // freopen("output.txt", "w", stdout);
    // #else
        // freopen("darwin.in", "r", stdin);
        // freopen("visitfj.out", "w", stdout);
    // #endif
}

constexpr int mod = 1e9 + 7, oo = 0x3f3f3f3f, N = 1e6 + 5;
const double pi = acos(-1), EPS = 1e-7;
constexpr ll OO = 0x3f3f3f3f3f3f3f3f;

constexpr int dy[] = { 0 , 1 , -1 , 0  , 1 , -1 , 1  , -1 };
constexpr int dx[] = { 1 , 0 ,  0 , -1 , 1 , -1 , -1 ,  1 };

vector<int>adj[N];
vector<int>in(N), out(N), preXor(N);
int id = 1;

void dfs(int u) {
    in[u] = id++;
    for (auto v : adj[u])dfs(v);
    out[u] = id - 1;
}

class Trie {
    struct Node {
        Node* child[2];
        set<int>ids;
        Node() {
            child[0] = child[1] = NULL;
        }
    };
    Node* root;
    int LOG;
public:
    Trie(int _LOG) :LOG(_LOG) { root = new Node(); }
    void insert(int u) {
        Node* v = root;
        int x = preXor[u];
        for (int bit = LOG - 1; bit >= 0; --bit) {
            int to = ((1 << bit) & x ? 1 : 0);
            if (v->child[to] == NULL) {
                v->child[to] = new Node();
            }
            v = v->child[to];
            v->ids.insert(in[u]);
        }
    }
    int query_max(int x, int u) {
        Node* v = root;
        int sum = 0;
        for (int bit = LOG - 1; bit >= 0; bit--) {
            int to = ((1 << bit) & x ? 0 : 1);
            if (v->child[to] != NULL and
                v->child[to]->ids.lower_bound(in[u]) != v->child[to]->ids.lower_bound(out[u] + 1)) {
                v = v->child[to], sum += to * (1 << bit);
            }
            else v = v->child[1 - to], sum += (1 - to) * (1 << bit);
        }
        return x ^ sum;
    }
};


void doWork(int T) {
    int q, n = 1;
    cin >> q;
    vector<pair<string, pair<int, int>>>Q(q);
    for (auto& i : Q) {
        cin >> i.first >> i.second.first >> i.second.second;
        if (i.first == "Add") {
            adj[i.second.first].push_back(++n);
            preXor[n] = preXor[i.second.first] ^ i.second.second;
        }
    }
    dfs(1);
    Trie tr(30);
    n = 1;
    tr.insert(n++);
    for (auto i : Q) {
        if (i.first == "Add") tr.insert(n++);
        else cout << tr.query_max(preXor[i.second.first], i.second.second) << ed;
    }
}

int main() {
    debug << "M3L4 El-Code MYTFHM4\n";
    Accept();
    int _ = 1;
    // cin >> _;
    for (int __ = 1;__ <= _;__++) {
        // cout << "Case " << __ << ": ";
        doWork(__);
        if (__ < _)cout << '\n';
        // cout << '\n';
    }
    Good_Bay 0;
}

• Subtask 1: 11 / 11
• Subtask 2: 22 / 22
• Subtask 3: 33 / 33
• Subtask 4: 44 / 44