Submission #872385

#	Time	Username	Problem	Language	Result	Execution time	Memory
872385		browntoad	Minerals (JOI19_minerals)	C++14	80 / 100	32 ms	2936 KiB

minerals

#include <bits/stdc++.h>
#include <minerals.h>
using namespace std;
#define ll long long
// #define int ll
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define REP(i, n) FOR(i, 0, n)
#define REP1(i, n) FOR(i, 1, n+1)
#define RREP(i, n) for (int i = (n)-1; i >= 0; i--)
#define RREP1(i, n) for (int i = (n); i >= 1; i--)
#define ALL(x) (x).begin(), (x).end()
#define SZ(x) (int)((x).size())
#define pb push_back
#define pii pair<int, int>
#define f first
#define s second
 
const ll maxn = 5e5+5;
const ll inf = (1ll<<60);
const ll mod = 1000992299;
 
int ou;
void run(vector<int> &L, vector<int> &R, bool x, bool y){
    if (SZ(L) == 1 && SZ(R) == 1){
        Answer(L[0], R[0]);
        return;
    }
    int mid = SZ(L)/2, b = 0, ret;
    vector<int> lll, lr, rl, rr;
    /*if (SZ(L) == 2 && SZ(R) == 2){
        if (x == 0 && y == 0){
            Query(L[0]);
            ret = Query(R[0]);
            if (ret == ou+2){
                Answer(L[0], R[1]);
                Answer(L[1], R[0]);
            }
            else{
                Answer(L[0], R[0]);
                Answer(L[1], R[1]);
            }
        }
        else if (x == 0 && y == 1){
            Query(R[1]);
            ret = Query(L[0]);
            if (ret == ou){
                Answer(L[0], R[1]);
                Answer(L[1], R[0]);
            }
            else{
                Answer(L[0], R[0]);
                Answer(L[1], R[1]);
            }
        }
        else if (x == 1 && y == 0){
            Query(L[1]);
            ret = Query(R[0]);
            if (ret == ou){
                Answer(L[0], R[1]);
                Answer(L[1], R[0]);
            }
            else{
                Answer(L[0], R[0]);
                Answer(L[1], R[1]);
            }
        }
        else {
            Query(L[0]);
            ret = Query(R[0]);
            if (ret == ou){
                Answer(L[0], R[1]);
                Answer(L[1], R[0]);
            }
            else{
                Answer(L[0], R[0]);
                Answer(L[1], R[1]);
            }
        }
        ou = ret;
        return;
    }
    */
    REP(i, mid){
        ou = Query(L[i]);
        lll.pb(L[i]);
    }
    FOR(i, mid, SZ(L)){
        rl.pb(L[i]);
    }
    if (x == 0 && y == 0){
        REP(i, SZ(R)){
            ret = Query(R[i]);
            if (ret == ou) lr.pb(R[i]);
            else rr.pb(R[i]);
            ou = ret;
        }
        run(lll, lr, 1, 1);
        run(rl, rr, 0, 1);
    }
    else if (x == 0 && y == 1){
        REP(i, SZ(R)){
            ret = Query(R[i]);
            if (ret == ou) lr.pb(R[i]);
            else rr.pb(R[i]);
            ou = ret;
        }
        run(lll, lr, 1, 0);
        run(rl, rr, 0, 0);
    }
    else if (x == 1 && y == 0){
        REP(i, SZ(R)){
            ret = Query(R[i]);
            if (ret != ou) lr.pb(R[i]);
            else rr.pb(R[i]);
            ou = ret;
        }
        run(lll, lr, 0, 1);
        run(rl, rr, 1, 1);
    }
    else {
        REP(i, SZ(R)){
            ret = Query(R[i]);
            if (ret != ou) lr.pb(R[i]);
            else rr.pb(R[i]);
            ou = ret;
        }
        run(lll, lr, 0, 0);
        run(rl, rr, 1, 0);
    }
}
void Solve(int N){
    vector<int> a, b;
    //REP1(i, N) a.pb(i);
    //FOR(i, N+1, 2*N+1) b.pb(i);
    int ret, prev = 0;
    REP1(i, 2*N){
        ret = Query(i);
        if (ret != prev) {
            a.pb(i);
            prev = ret;
        }
        else {
            b.pb(i);
        }
    }
    ou = prev;
    //REP(i, SZ(a)) Query(a[i]);
    run(a, b, 1, 1);
}

Compilation message (stderr)

minerals.cpp: In function 'void run(std::vector<int>&, std::vector<int>&, bool, bool)':
minerals.cpp:28:24: warning: unused variable 'b' [-Wunused-variable]
   28 |     int mid = SZ(L)/2, b = 0, ret;
      |                        ^

• Subtask 1: 6 / 6
• Subtask 2: 25 / 25
• Subtask 3: 9 / 9
• Subtask 4: 30 / 30
• Subtask 5: 5 / 5
• Subtask 6: 5 / 5
• Subtask 7: 0 / 5
• Subtask 8: 0 / 5
• Subtask 9: 0 / 10