Submission #871758

#	Time	Username	Problem	Language	Result	Execution time	Memory
871758		mertozel	Lutrija (COCI19_lutrija)	C++11	42 / 70	2057 ms	604 KiB

lutrija

    #include <bits/stdc++.h>
    using namespace std;
    using ll = long long;
     
    vector <int> ans;
     
    int isPrime(ll a) {
     
    	if(a < 2) return 0;
    	if(a <= 3) return 1;
    	for(int i = 2; i * i <= a; i++) {
    		if (a % i == 0) return 0; 
    	}
    	return 1;
    }
     
    void finish() {
    	cout << -1;
    	exit(0);
    }
     
    void ex() {
    	exit(0);
    }
    void check(vector <ll> ans, vector<ll> ans1) {
    	
    	ll a = ans.back();
    	ll b = ans1.back();
     
    	if(a <= 1 || b <= 1) return;
    	if(a == 2 && b == 2) {ans.push_back(5); goto here;}
    	if(isPrime(abs(a-b))) {
     
            here:
    		cout << ans.size() + ans1.size() << "\n";
    		for(ll i : ans) cout << i << " ";
    		reverse(ans1.begin(), ans1.end());
    		for(ll i : ans1) cout << i << " ";
    		ex();
    	}
     
    	if(isPrime(a-2)) {
    		ans.push_back(2);
    		check(ans, ans1);
    		ans.pop_back();
    	}
     
    	if(isPrime(a+2)) {
    		ans.push_back(a+2);
    		check(ans, ans1);
    		ans.pop_back();
    	}  
     
    	if(isPrime(b-2)) {
    		ans1.push_back(2);
    		check(ans, ans1);
    		ans1.pop_back();
    	}
     
    	if(isPrime(b+2)) {
    		ans1.push_back(b+2);
    		check(ans, ans1);
    		ans1.pop_back();
    	}
     
    	return;
     
    }
     
    int main() {
     
    	ios_base::sync_with_stdio(0);
    	cin.tie(0);
    	cout.tie(0);
    	
    	ll a, b;
    	cin >> a >> b;
     
    	if(a % 2 == 0 && b % 2 == 0) finish();
     
    	if(isPrime(abs(a-b))) {
    		cout << "2\n" << a << " " << b  << "\n";
    		return 0;
    	}
     
    	vector <ll> ans, ans1;
    	ans.push_back(a);
    	ans1.push_back(b);
     
    	check(ans, ans1);
    	finish();
     
     
     
     
     
    	return 0;
    }

• Subtask 1: 7 / 7
• Subtask 2: 7 / 7
• Subtask 3: 7 / 7
• Subtask 4: 7 / 7
• Subtask 5: 7 / 7
• Subtask 6: 7 / 7
• Subtask 7: 0 / 7
• Subtask 8: 0 / 7
• Subtask 9: 0 / 7
• Subtask 10: 0 / 7