# | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
871229 | 2023-11-10T09:44:45 Z | Lib | Rarest Insects (IOI22_insects) | C++17 | 0 ms | 344 KB |
#include <bits/stdc++.h> #include "insects.h" //#include "stub.cpp" using namespace std; vector <int> PrevIndexIn,PrevIndexOut,RemainingInsects; int InMachine[2003]; int n; int TypeCount=0; int CurrentInMachine=0; int PossibleMincount(int cnt){ PrevIndexIn.clear(); PrevIndexOut.clear(); //Pushing insects inside the machine, keeping track of the ones being putted inside for this iteration of binary searching for(int i=0;i<RemainingInsects.size();i++){ move_inside(i); InMachine[i]=1; PrevIndexIn.push_back(i); if(press_button()>cnt){ PrevIndexIn.pop_back(); PrevIndexOut.push_back(i); InMachine[i]=0; move_outside(i); } } CurrentInMachine=0; for(int i=0;i<n;i++){ CurrentInMachine+=InMachine[i]; } RemainingInsects.clear(); if(CurrentInMachine<cnt*TypeCount){ //There clearly exist a type of insect with cardinality less than cnt, so the answer is less than cnt. Removing insects from last iteration. while(!PrevIndexIn.empty()){ InMachine[PrevIndexIn.back()]=0; move_outside(PrevIndexIn.back()); PrevIndexIn.pop_back(); } for(int i=0;i<n;i++){ if(!InMachine[i]){ RemainingInsects.push_back(i); } } return 0; }else if(CurrentInMachine==cnt*TypeCount){ //As every type of insects has at least cnt insects, the answer is at least cnt. Just return true for(int i=0;i<n;i++){ if(!InMachine[i]){ RemainingInsects.push_back(i); } } return 1; } } int min_cardinality(int N){ //Remember to initialize as this is multitest for(int i=0;i<=2000;i++){ InMachine[i]=0; } int l,r,mid; n=N; l=1; //Phase 1: Determining the amount of different types of insects for(int i=0;i<n;i++){ move_inside(i); InMachine[i]=1; PrevIndexIn.push_back(i); if(press_button()>1){ move_outside(i); InMachine[i]=0; PrevIndexIn.pop_back(); PrevIndexOut.push_back(i); } } for(int i=0;i<n;i++){ if(!InMachine[i]){ RemainingInsects.push_back(i); } } TypeCount=PrevIndexIn.size(); r=(n/TypeCount); //Phase 2: Binary search for the answer while(r-l>1){ mid=(l+r)/2; if(PossibleMincount(mid)){ l=mid; }else{ r=mid-1; } } if(PossibleMincount(r)){ return r; }else{ return l; } }
Compilation message
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 0 ms | 344 KB | Wrong answer. |
2 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Incorrect | 0 ms | 344 KB | Wrong answer. |
2 | Halted | 0 ms | 0 KB | - |
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Correct | 0 ms | 344 KB | Output is correct |
2 | Incorrect | 0 ms | 344 KB | Wrong answer. |
3 | Halted | 0 ms | 0 KB | - |