Submission #871116

#	Time	Username	Problem	Language	Result	Execution time	Memory
871116		HorizonWest	Let's Win the Election (JOI22_ho_t3)	C++17	56 / 100	2595 ms	1002744 KiB

Main

#include <bits/stdc++.h>
using namespace std;
 
#define endl '\n'
#define db double
#define ll __int128
#define int long long
#define pb push_back
#define fs first
#define sd second
#define Mod long(1e9 + 7)
#define all(x) x.begin(), x.end()
#define unvisited long(-1)
#define Eps double(1e-9)
#define _for(i, n) for(int i = 0; i < (n); i++)
#define dbg(x) cout << #x ": " << x << endl;
 
const int Max = 1e6 + 7, Inf = 1e9 + 7;
 
void print(bool x) { cout << (x ? "YES" : "NO") << endl; }
 
string tostring (__int128 x)
{
    string ans = "";
    while(x > 0)
    {
        ans += (x % 10 + '0');
        x /= 10;
    }
    reverse(all(ans));
    return ans;
}
 
void printdb(double ans, int k)
{
    cout << setiosflags(ios::fixed)
         << setiosflags(ios::showpoint)
         << setprecision(k) << ans << endl;
}
 
void solve()
{
    int n, m; cin >> n >> m; 
    vector <pair<db, db>> v(n); 
    for(auto& u : v) 
    {
        cin >> u.sd >> u.fs;
        if(u.fs == -1) u.fs = Inf;  
    } 
    sort(all(v)); db ans = Inf; 

    for(db l = 1; l <= m; l++)
    {
        vector <vector<vector<db>>> dp(n + 2, vector <vector<db>> (
            m + 2, vector <db> (m + 2, Inf)
        )); dp[0][1][0] = 0.000; 
        
        for(db i = 0; i < n; i++)
        {
            for(db j = 1; j <= l; j++)
            {
                for(db k = 0; k <= m; k++)
                {
                    dp[i+1][j][k] = min(dp[i+1][j][k], dp[i][j][k]);  
                    dp[i+1][j][k+1] = min(dp[i+1][j][k+1], dp[i][j][k] + v[i].sd / l); 
                    if(v[i].fs != Inf)
                    {
                        dp[i+1][j+1][k+1] = min(dp[i+1][j+1][k+1], dp[i][j][k] + v[i].fs / j); 
                    } 
                }
            }
            ans = min(ans, dp[i+1][l][m]); 
        }
    }
 
    printdb(ans, 5); 
}
 
int32_t main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);
 
    int Q = 1; //cin >> Q;
 
    while (Q--)
    {
        solve();
    }
 
    return 0;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 5
• Subtask 3: 11 / 11
• Subtask 4: 12 / 12
• Subtask 5: 33 / 33
• Subtask 6: 0 / 11
• Subtask 7: 0 / 23