Submission #868738

#TimeUsernameProblemLanguageResultExecution timeMemory
868738hazzleSwap (BOI16_swap)C++17
68 / 100
564 ms262144 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> //#pragma GCC optimize("Ofast,unroll-loops") //#pragma GCC target("avx,avx2,fma") using namespace std; using namespace __gnu_pbds; #define fi first #define se second #define all(m) (m).begin(), (m).end() #define rall(m) (m).rbegin(), (m).rend() #define vec vector #define sz(a) (int) (a).size() #define mpp make_pair #define mt t make_tuple #define RA ranges typedef long long ll; typedef long double ld; typedef unsigned long long ull; typedef pair <ll, ll> pll; typedef pair <int, int> pii; typedef tuple <int, int, int> tui; template <typename T> using prq = priority_queue <T>; template <typename T> using pgq = priority_queue <T, vec <T>, greater <T>>; template <typename T> using oset = tree <T, null_type, less <T>, rb_tree_tag, tree_order_statistics_node_update>; #define ook order_of_key template <typename T> bool umin(T &a, T b) { return a > b ? a = b, 1 : 0; } template <typename T> bool umax(T &a, T b) { return a < b ? a = b, 1 : 0; } inline int solve(){ int n; cin >> n; vec <int> a(n + 1); for (int i = 1; i <= n; ++i) cin >> a[i]; auto mrg = [&](int x, vec <int> lf, vec <int> rt){ vec <int> res(1 + sz(lf) + sz(rt)); res[0] = x; int p1 = 0, p2 = 0; int st = 1, pt = 1; while(pt < sz(res)){ for (int i = 0; i < st && p1 < sz(lf) && pt < sz(res); ++i){ res[pt++] = lf[p1++]; } for (int i = 0; i < st && p2 < sz(rt) && pt < sz(res); ++i){ res[pt++] = rt[p2++]; } st <<= 1; } return res; }; vec <map <int, vec <int>>> dp(n + 1); auto _dp = [&](auto &&_dp, int i, int ai) -> vec <int> { if (dp[i].count(ai)) return dp[i][ai]; int ls = 2 * i, rs = 2 * i + 1; if (ls > n) return dp[i][ai] = {ai}; if (rs > n) return dp[i][ai] = {min(ai, a[ls]), max(ai, a[ls])}; if (ai < min(a[ls], a[rs])){ return dp[i][ai] = mrg(ai, _dp(_dp, ls, a[ls]), _dp(_dp, rs, a[rs])); } if (a[ls] < a[rs]){ return dp[i][ai] = mrg(a[ls], _dp(_dp, ls, ai), _dp(_dp, rs, a[rs])); } return dp[i][ai] = min(mrg(a[rs], _dp(_dp, ls, a[ls]), _dp(_dp, rs, ai)), mrg(a[rs], _dp(_dp, ls, ai), _dp(_dp, rs, a[ls]))); auto lol1 = _dp(_dp, ls, a[ls]); auto lol2 = _dp(_dp, rs, a[rs]); auto lol3 = _dp(_dp, ls, ai); auto lol4 = _dp(_dp, rs, ai); auto lol5 = _dp(_dp, rs, a[ls]); auto op1 = mrg(ai, lol1, lol2); auto op2 = mrg(a[ls], lol3, lol2); auto op3 = mrg(a[rs], lol1, lol4); auto op4 = mrg(a[rs], lol3, lol5); // 1 2 3 // 2 1 3 // 3 1 2 // cout << i << " " << ai << ":\n"; // cout << " "; for (auto &x: op1) cout << x << " "; cout << "\n"; // cout << " "; for (auto &x: op2) cout << x << " "; cout << "\n"; // cout << " "; for (auto &x: op3) cout << x << " "; cout << "\n"; return dp[i][ai] = min({op1, op2, op3, op4}); }; vec <int> res = _dp(_dp, 1, a[1]); for (auto &i: res) cout << i << " "; return 0; } inline void precalc(){} signed main(){ //ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); int tst = 1; //cin >> tst; precalc(); while(tst--) solve(); return 0; }
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