Submission #868437

#	Time	Username	Problem	Language	Result	Execution time	Memory
868437		t6twotwo	Two Currencies (JOI23_currencies)	C++17	100 / 100	2964 ms	201388 KiB

currencies

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
template <class S, S (*f)(S, S), S e>
struct PST {
    struct T {
        T *l, *r; S s;
        T() : s() {l = r = nullptr;}
        T(const S &v) : s(v) {l = r = nullptr;}
        T(T *t) : l(t->l), r(t->r), s(t->s) {}
        T(T *a, T *b) : l(a), r(b), s() {
            if (l) s = f(s, l->s);
            if (r) s = f(s, r->s);
        }
    };
    int n;
    vector<T*> rts;
    PST(int m) : PST(vector<S>(m, e)) {
    }
    PST(const vector<S> &a) : n(a.size()) {
        function<T*(int, int)> bld = [&](int l, int r) {
            if (l + 1 == r) {
                return new T(a[l]);
            }
            int m = (l + r) / 2;
            return new T(bld(l, m), bld(m, r));
        };
        rts.push_back(bld(0, n));
    }
    T* set(T *i, int l, int r, int p, const S &v) {
        if (l + 1 == r) {
            return new T(v);
        }
        int m = (l + r) / 2;
        if (p < m) {
            return new T(set(i->l, l, m, p, v), i->r);
        } else {
            return new T(i->l, set(i->r, m, r, p, v));
        }
    }
    T* upd(T *i, int l, int r, int p, const S &v) {
        if (l + 1 == r) {
            return new T(f(i->s, v));
        }
        int m = (l + r) / 2;
        if (p < m) {
            return new T(upd(i->l, l, m, p, v), i->r);
        } else {
            return new T(i->l, upd(i->r, m, r, p, v));
        }
    }
    S qry(T *i, int l, int r, int L, int R) {
        if (R <= l || r <= L) {
            return e;
        }
        if (L <= l && r <= R) {
            return i->s;
        }
        int m = (l + r) / 2;
        return f(qry(i->l, l, m, L, R), qry(i->r, m, r, L, R));
    }
    int lst() {
        return rts.size() - 1;
    }
    int cpy(int k) {
        rts.push_back(new T(rts[k]));
        return rts.size() - 1;
    }
    void set(int k, int i, const S &v) {
        rts[k] = set(rts[k], 0, n, i, v);
    }
    void upd(int k, int i, const S &v) {
        rts[k] = upd(rts[k], 0, n, i, v);
    }
    S qry(int k, int l, int r) {
        return qry(rts[k], 0, n, l, r);
    }
};
ll F(ll x, ll y) {
    return x + y;
}
template<int SZ, bool VALS_IN_EDGES> struct HLD { 
	int N; vector<int> adj[SZ];
	int par[SZ], root[SZ], depth[SZ], sz[SZ], ti;
	int pos[SZ]; vector<int> rpos; // rpos not used but could be useful
	void ae(int x, int y) { adj[x].push_back(y), adj[y].push_back(x); }
	void dfsSz(int x) { 
		sz[x] = 1; 
		for(auto &y:adj[x]) {
			par[y] = x; depth[y] = depth[x]+1;
			adj[y].erase(find(adj[y].begin(), adj[y].end(),x)); /// remove parent from adj list
			dfsSz(y); sz[x] += sz[y];
			if (sz[y] > sz[adj[x][0]]) swap(y,adj[x][0]);
		}
	}
	void dfsHld(int x) {
		pos[x] = ti++; rpos.push_back(x);
		for(auto &y:adj[x]) {
			root[y] = (y == adj[x][0] ? root[x] : y);
			dfsHld(y); }
	}
	void init(int _N, int R = 0) { N = _N; 
		par[R] = depth[R] = ti = 0; dfsSz(R); 
		root[R] = R; dfsHld(R); 
	}
	int lca(int x, int y) {
		for (; root[x] != root[y]; y = par[root[y]])
			if (depth[root[x]] > depth[root[y]]) swap(x,y);
		return depth[x] < depth[y] ? x : y;
	}
	/// int dist(int x, int y) { // # edges on path
	/// 	return depth[x]+depth[y]-2*depth[lca(x,y)]; }
	// LazySeg<ll,SZ> tree; // segtree for sum
	template <class BinaryOp>
	void processPath(int x, int y, BinaryOp op) {
		for (; root[x] != root[y]; y = par[root[y]]) {
			if (depth[root[x]] > depth[root[y]]) swap(x,y);
			op(pos[root[y]],pos[y]); }
		if (depth[x] > depth[y]) swap(x,y);
		op(pos[x]+VALS_IN_EDGES,pos[y]); 
	}
	// void modifyPath(int x, int y, int v) { 
	// 	processPath(x,y,[this,&v](int l, int r) { 
	// 		tree.upd(l,r,v); }); }
	// ll queryPath(int x, int y) { 
	// 	ll res = 0; processPath(x,y,[this,&res](int l, int r) { 
	// 		res += tree.query(l,r); });
	// 	return res; }
	// void modifySubtree(int x, int v) { 
	// 	tree.upd(pos[x]+VALS_IN_EDGES,pos[x]+sz[x]-1,v); }
};
int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int N, M, Q;
    cin >> N >> M >> Q;
    vector<pair<int, int>> edges(N - 1);
    vector<vector<int>> adj(N);
    for (int i = 0; i < N - 1; i++) {
        int x, y;
        cin >> x >> y;
        x--, y--;
        edges[i] = {x, y};
        adj[x].push_back(i);
        adj[y].push_back(i);
    }
    vector<pair<int, int>> ch(M);
    for (int i = 0; i < M; i++) {
        int p, c;
        cin >> p >> c;
        ch[i] = {c, p - 1};
    }
    sort(ch.begin(), ch.end());
    vector<int> t(N - 1);
    {
        auto dfs = [&](auto dfs, int x, int p) -> void {
            for (int z : adj[x]) {
                auto [u, v] = edges[z];
                int y = x ^ u ^ v;
                if (y != p) {
                    t[z] = y;
                    dfs(dfs, y, x);
                }
            }
        };
        dfs(dfs, 0, -1);
    }
    HLD<1000000, 1> hld;
    for (int i = 0; i < N; i++) {
        for (int &j : adj[i]) {
            auto [x, y] = edges[j];
            j = i ^ x ^ y;
            if (j < i) {
                hld.ae(i, j);
            }
        }
    }
    hld.init(N);
    PST<ll, F, 0> q(N);
    for (int i = 0; i < M; i++) {
        auto [c, p] = ch[i];
        q.upd(q.cpy(q.lst()), hld.pos[t[p]], c);
    }
    auto get = [&](int x, int y, int z) -> ll {
        ll s = 0;
        hld.processPath(x, y, [&](int l, int r) {
            s += q.qry(z, l, r + 1);
        });
        return s;
    };
    vector<int> S(Q), T(Q), X(Q), a(Q);
    vector<ll> Y(Q);
    for (int i = 0; i < Q; i++) {
        cin >> S[i] >> T[i] >> X[i] >> Y[i];
        S[i]--, T[i]--;
        int lo = 0, hi = M;
        while (lo < hi) {
            int mi = (lo + hi + 1) / 2;
            if (get(S[i], T[i], mi) <= Y[i]) {
                lo = mi;
            } else {
                hi = mi - 1;
            }
        }
        a[i] = lo;
    }
    vector<ll> ans(Q);
    vector<vector<int>> f(M + 1);
    for (int i = 0; i < Q; i++) {
        f[a[i]].push_back(i);
    }
    q = PST<ll, F, 0>(N);
    for (int i = M; i >= 0; i--) {
        if (i < M) {
            auto [c, p] = ch[i];
            q.upd(q.cpy(q.lst()), hld.pos[t[p]], 1);
        }
        for (int j : f[i]) {
            ans[j] = max(-1LL, X[j] - get(S[j], T[j], q.lst()));
        }
    }
    for (int i = 0; i < Q; i++) {
        cout << ans[i] << "\n";
    }
    return 6/22;
}

• Subtask 1: 10 / 10
• Subtask 2: 28 / 28
• Subtask 3: 30 / 30
• Subtask 4: 32 / 32