Submission #867132

#	Time	Username	Problem	Language	Result	Execution time	Memory
867132		Lalic	Prize (CEOI22_prize)	C++17	0 / 100	623 ms	169724 KiB

Main

#include <bits/stdc++.h>
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
using namespace std;

#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define all(x) x.begin(), x.end()

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

const int MAXN = 1e6+10;
const int INF = 0x3f3f3f3f;
const ll LINF = 0x3f3f3f3f3f3f3f3f;
const int MOD = 1e9+7;

vector<vector<int>> adj;
vector<int> escolha;
int n, k, q, t;

int pai[20][MAXN], nvl[MAXN];

void build(int ver, int prev=0){
	nvl[ver]=nvl[prev]+1;

	for(auto u : adj[ver]){
		build(u, ver);
	}
}

void dfs(int ver){
	escolha.pb(ver);
	if((int)escolha.size()==k)
		return;

	for(auto u : adj[ver]){
		dfs(u);

		if((int)escolha.size()==k)
			return;
	}
}

int lca(int a, int b){
	if(nvl[a]>nvl[b])
		swap(a, b);

	int diff=nvl[b]-nvl[a];
	for(int i=0;i<=19;i++){
		if((diff&(1<<i))){
			b=pai[i][b];
		}
	}

	if(a==b)
		return a;

	for(int i=19;i>=0;i--){
		if(pai[i][a]!=pai[i][b]){
			a=pai[i][a];
			b=pai[i][b];
		}
	}

	return pai[0][a];
}

void solve(){
	cin >> n >> k >> q >> t;

	int root=-1;
	adj.resize(n+1);
	for(int i=1;i<=n;i++){
		int x; cin >> x;
		pai[0][i]=x;
		if(x==-1){
			pai[0][i]=i;
			root=i;
			continue;
		}
		adj[x].pb(i);
	}

	build(root);

	for(int i=1;i<=19;i++)
		for(int j=1;j<=n;j++)
			pai[i][j]=pai[i-1][pai[i-1][j]];

	for(int i=1;i<=n;i++){
		int x; cin >> x;
	}

	dfs(root);

	for(int i=0;i<k-1;i++)
		cout << escolha[i] << " ";
	cout << escolha[k-1] << endl;

	for(int i=1;i<k;i++)
		cout << "? " << escolha[0] << " " << escolha[i] << endl;
	cout << "!" << endl;

	vector<int> dist(n+1);
	for(int i=1;i<k;i++){
		int baboseira[3];
		for(int j=0;j<3;j++)
			cin >> baboseira[j];
		cin >> dist[escolha[i]];
	}

	vector<pii> resp;
	for(int i=0;i<t;i++){
		int a, b; cin >> a >> b;
		int l=lca(a, b);

		cout << dist[a]+dist[b]-2*dist[l] << endl;
	}
}

int main(){
	ios_base::sync_with_stdio(false); cin.tie(NULL);

	int tt=1;
	// cin >> tt;
	while(tt--)
		solve();
}

/*
4 4 3 3                                                                                                                                                                                                                            
2 -1 2 1                                                                                                                                                                                                                           
2 -1 2 1                                                                                                                                                                                                                           

0 3 0 3                                                                                                                                                                                                                            
0 10 0 10                                                                                                                                                                                                                          
0 1 0 1                                                                                                                                                                                                                            
1 4                                                                                                                                                                                                                                
2 4                                                                                                                                                                                                                                
3 4
*/

• Subtask 1: 0 / 10
• Subtask 2: 0 / 25
• Subtask 3: 0 / 19
• Subtask 4: 0 / 22
• Subtask 5: 0 / 24