Submission #866378

#	Time	Username	Problem	Language	Result	Execution time	Memory
866378		vjudge1	Selotejp (COCI20_selotejp)	C++17	110 / 110	31 ms	88520 KiB

Main

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#include <bits/stdc++.h>

using namespace std;
#define ll long long
#define endl "\n"

const int N = 10;
const int p = 1e9 + 7;

ll dp[1001][11][1<<10];
vector<string> vec(1001);




void solve(){
    int n, m;
    cin >> n >> m;
    int mask = 1 << m;
    for(int i = 0; i < m; i++){
        vec[0] += '.';
    }
    for(int i = 1; i <= n; i++){
        cin >> vec[i];
    }
    for(int i = 0; i < mask; i++){
        dp[0][m][i] = 0;
    }
    for(int i = 1; i <= n; i++){
        for(int j = 1; j <= m; j++){
            for(int k = 0; k < mask; k++){
                int nm = k ^ (1 << (j - 1));
                if(vec[i][j - 1] == '#'){
                    if(k & (1 << (j - 1))){
                        if(j == 1){
                            dp[i][j][k] = min(dp[i - 1][m][k], dp[i - 1][m][nm]) + 1;
                            if(vec[i - 1][j - 1] == '#'){
                                dp[i][j][k] = min(dp[i][j][k], dp[i - 1][m][k]);
                            }
                        }else{
                            dp[i][j][k] = min(dp[i][j - 1][k], dp[i][j - 1][nm]) + 1;
                            if(vec[i - 1][j - 1] == '#'){
                                dp[i][j][k] = min(dp[i][j][k], dp[i][j - 1][k]);
                            }
                        }
                    }else{
                        if(j == 1){
                            dp[i][j][k] =  min(dp[i - 1][m][k], dp[i - 1][m][nm]) + 1;
                        }else{
                            dp[i][j][k] = min(dp[i][j - 1][k], dp[i][j - 1][nm]) + 1;
                            if(vec[i][j - 2] == '#' && (k & (1 << (j - 2))) == 0){
                                dp[i][j][k] -= 1;
                            }
                        }
                    }
                }else{
                    if(j == 1){
                        dp[i][j][k] = min(dp[i - 1][m][k], dp[i - 1][m][nm]);
                    }else{
                        dp[i][j][k] = min(dp[i][j - 1][k], dp[i][j - 1][nm]);
                    }
                }
            }
        }
    }
    ll res = n*m;
    for(int i = 0; i < mask; i++){
        res = min(res, dp[n][m][i]);
    }
    cout << res << endl;
    
    
}

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(NULL);
    int t = 1;
    while(t--){
        solve();
    }

    return 0;
}

• Subtask 1: 35 / 35
• Subtask 2: 35 / 35
• Subtask 3: 40 / 40