This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define ll long long
#define ld long double
#define pb push_back
#define fi first
#define se second
#define en '\n'
#define sp ' '
#define tb '\t'
#define ri(n) int n; cin >> n
#define rl(n) ll n; cin >> n
#define rs(s) string s; cin >> s
#define rc(c) char c; cin >> c
#define rv(v) for (auto &x : v) cin >> x
#define pven(v) for (auto x : v) cout << x << en
#define pv(v) for (auto x : v) cout << x << sp; cout << en
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define yes cout << "YES" << en
#define no cout << "NO" << en
#define smin(a, b) a = min(a, b)
#define smax(a, b) a = max(a, b)
#define ssort(a, b) if (a < b) swap(a, b)
#define bitcnt(a) (__builtin_popcountll(a))
#define bithigh(a) (63-__builtin_clzll(a))
#define lg bithigh
#define highpow(a) (1LL << (ll)lg(a))
using namespace std;
struct T{
int n, mx;
vector<int> on, L, R;
void Insert(int i){
on[i] = 1;
int prev = (i ? i-1 : n-1);
int next = (i < n-1 ? i+1 : 0);
int l = (on[prev] ? L[prev] : i);
int r = (on[next] ? R[next] : i);
if (n == 1 || l == next){
mx = n;
return;
}
smax(mx, (r-l + n) % n + 1);
R[l] = r;
L[r] = l;
}
int Get() const { return mx; }
T(int s){
n = s;
mx = 0;
on.assign(n, 0);
L.resize(n);
R.resize(n);
}
};
const ll LINF = 4e18;
const int mxN = 1e6+10, mxD = 5e3+10, INF = 2e9;
int n, m, d, a[mxN], b[mxN], is_free[mxD][mxD];
set<int> s;
vector<int> K[mxN];
void Solve(){
cin >> n >> m >> d;
for (int i = 0; i < n; i++)
cin >> a[i] >> b[i];
for (int i = n; i < n+m; i++){
cin >> a[i] >> b[i];
K[a[i]].pb(i);
}
for (int i = 0; i < d; i++){
for (int j : K[i])
s.insert(b[j]);
for (int j = 0; j < d; j++){
if (s.empty()){
is_free[i][j] = j;
continue;
}
is_free[i][j] = *s.rbegin();
if (*s.begin() == j){
s.erase(s.begin());
s.insert(j+d);
}
}
s.clear();
}
for (int i = 0; i < n; i++)
s.insert(a[i]);
for (int i : s)
for (int j = 0; j < d; j++)
is_free[i][j] = 2*d;
s.clear();
for (int i = 0; i < n; i++)
s.insert(b[i]);
int ans = d*d;
for (int i = 0; i < d; i++){
vector<vector<int> > t(2*d);
for (int j = 0; j < d; j++)
if (is_free[j][i] < 2*d)
t[is_free[j][i]].pb(j);
auto x = *s.rbegin();
T pool(d);
for (int j = 0; j <= x; j++)
for (int k : t[j]) pool.Insert(k);
smin(ans, (x-i+1) * (d - pool.Get()));
for (int j = x+1; j < i+d; j++){
for (int k : t[j])
pool.Insert(k);
smin(ans, (j-i+1) * (d - pool.Get()));
}
if (*s.begin() == i){
s.erase(s.begin());
s.insert(i+d);
}
}
cout << ans << en;
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0); cout.tie(0); cerr.tie(0);
cout << setprecision(12) << fixed;
cerr << setprecision(12) << fixed;
cerr << "Started!" << endl;
int t = 1;
//cin >> t;
while (t--)
Solve();
return 0;
}
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