# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
863132 | Alfraganus | Bigger segments (IZhO19_segments) | C++14 | 0 ms | 344 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#pragma GCC optimize("unroll-loops")
#pragma gcc optimize("Ofast")
#pragma GCC optimization("Ofast")
#pragma optimize(Ofast)
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define str string
#define fastio ios::sync_with_stdio(0), cin.tie(0);
#define fs first
#define ss second
#define endl '\n'
#define all(x) (x).begin(), (x).end()
#define len(x) x.size()
#define print(a) \
for (auto &x : a) \
cout << x << " "; \
cout << endl;
#define printmp(a) \
for (auto &x : a) \
cout << x.fs << " " << x.ss << endl;
const int mod = 1e9 + 7;
void solve(){
/*
Our small boy Askhat noticed an interesting phenomenon — trying to cover an array with “jumps” of bigger and bigger sums may not be as simple as it seems. Of course, now you need to find a way to do it. You are given a sequence of positive integer numbers of length N.
Divide the given sequence into the maximal number of segments so that:
1. Every element of the sequence belongs to exactly one segment.
2. Sum of the numbers in every segment, except for the first one, is not less than in the previous
*/
int n;
cin >> n;
vector<int> a(n);
for(int i = 0; i < n; i++){
cin >> a[i];
}
int ans = 0;
for(int i = 0; i < n; i++){
int sum = 0;
for(int j = i; j < n; j++){
sum += a[j];
ans = max(ans, sum);
}
}
cout << ans;
}
signed main(){
fastio
int t = 1;
// cin >> t;
while(t --){
solve();
cout << endl;
}
}
Compilation message (stderr)
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