Submission #859821

#	Time	Username	Problem	Language	Result	Execution time	Memory
859821		blackslex	Type Printer (IOI08_printer)	C++17	100 / 100	112 ms	164964 KiB

printer

#include<bits/stdc++.h>
 
using namespace std;
using tp = tuple<int, int, char>;
 
const int N = 3e4 + 5, C = 26;
int n, idx;
string s;
vector<char> ans;
 
struct node {
    int nxt[C], lv[C];
    bool end;
    node() {for (int i = 0; i < C; i++) nxt[i] = lv[i] = 0; end = 0;}
} t[N * C];
 
void add (string s) {
    int cur = 0;
    for (auto &e: s) e -= 'a';
    for (auto &e: s) {
        if (!t[cur].nxt[e]) t[cur].nxt[e] = ++idx; t[cur].lv[e] = max(t[cur].lv[e], (int) s.size()); cur = t[cur].nxt[e];
    }
    t[cur].end = 1;
}
 
void dfs (int cur) {
    if (t[cur].end) ans.emplace_back('P');
    vector<tp> v;
    for (int i = 0; i < C; i++) if (t[cur].nxt[i]) v.emplace_back(t[cur].lv[i], t[cur].nxt[i], i + 'a');
    sort(v.begin(), v.end());
    for (auto &[lv, nxt, c]: v) ans.emplace_back(c), dfs(nxt), ans.emplace_back('-');
}
 
int main() {
    scanf("%d", &n);
    for (int i = 0; i < n; i++) cin >> s, add(s);
    dfs(0);
    while (ans.back() == '-') ans.pop_back();
    printf("%d\n", ans.size());
    for (auto &e: ans) printf("%c\n", e);
}

Compilation message (stderr)

printer.cpp: In function 'void add(std::string)':
printer.cpp:21:25: warning: array subscript has type 'char' [-Wchar-subscripts]
   21 |         if (!t[cur].nxt[e]) t[cur].nxt[e] = ++idx; t[cur].lv[e] = max(t[cur].lv[e], (int) s.size()); cur = t[cur].nxt[e];
      |                         ^
printer.cpp:21:40: warning: array subscript has type 'char' [-Wchar-subscripts]
   21 |         if (!t[cur].nxt[e]) t[cur].nxt[e] = ++idx; t[cur].lv[e] = max(t[cur].lv[e], (int) s.size()); cur = t[cur].nxt[e];
      |                                        ^
printer.cpp:21:9: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
   21 |         if (!t[cur].nxt[e]) t[cur].nxt[e] = ++idx; t[cur].lv[e] = max(t[cur].lv[e], (int) s.size()); cur = t[cur].nxt[e];
      |         ^~
printer.cpp:21:52: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
   21 |         if (!t[cur].nxt[e]) t[cur].nxt[e] = ++idx; t[cur].lv[e] = max(t[cur].lv[e], (int) s.size()); cur = t[cur].nxt[e];
      |                                                    ^
printer.cpp:21:62: warning: array subscript has type 'char' [-Wchar-subscripts]
   21 |         if (!t[cur].nxt[e]) t[cur].nxt[e] = ++idx; t[cur].lv[e] = max(t[cur].lv[e], (int) s.size()); cur = t[cur].nxt[e];
      |                                                              ^
printer.cpp:21:81: warning: array subscript has type 'char' [-Wchar-subscripts]
   21 |         if (!t[cur].nxt[e]) t[cur].nxt[e] = ++idx; t[cur].lv[e] = max(t[cur].lv[e], (int) s.size()); cur = t[cur].nxt[e];
      |                                                                                 ^
printer.cpp:21:119: warning: array subscript has type 'char' [-Wchar-subscripts]
   21 |         if (!t[cur].nxt[e]) t[cur].nxt[e] = ++idx; t[cur].lv[e] = max(t[cur].lv[e], (int) s.size()); cur = t[cur].nxt[e];
      |                                                                                                                       ^
printer.cpp: In function 'int main()':
printer.cpp:39:14: warning: format '%d' expects argument of type 'int', but argument 2 has type 'std::vector<char>::size_type' {aka 'long unsigned int'} [-Wformat=]
   39 |     printf("%d\n", ans.size());
      |             ~^     ~~~~~~~~~~
      |              |             |
      |              int           std::vector<char>::size_type {aka long unsigned int}
      |             %ld
printer.cpp:35:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   35 |     scanf("%d", &n);
      |     ~~~~~^~~~~~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 10 / 10
• Subtask 5: 10 / 10
• Subtask 6: 10 / 10
• Subtask 7: 10 / 10
• Subtask 8: 10 / 10
• Subtask 9: 10 / 10
• Subtask 10: 10 / 10