Submission #857657

#TimeUsernameProblemLanguageResultExecution timeMemory
857657boris_mihovPeru (RMI20_peru)C++17
0 / 100
6 ms12892 KiB
#include "peru.h" #include <algorithm> #include <iostream> #include <numeric> #include <cassert> #include <vector> #include <queue> #include <stack> #include <set> typedef long long llong; const int MAXN = 2500000 + 10; const int MOD = 1e9 + 7; const llong INF = 1e18; const int INTINF = 1e9; int n, k; int a[MAXN]; llong dp[MAXN]; std::deque <int> dq; int fromWhere[MAXN]; struct WindowMIN { std::stack <llong> right; std::deque <llong> left; void pushLeft(llong value) { while (left.size() && left.back() > value) { left.pop_back(); } left.push_back(value); } void popLeft() { while (left.empty()); left.pop_front(); } void pushRight(llong value) { if (right.size()) right.push(std::max(right.top(), value)); else right.push(value); } void popRight() { while (right.empty()); right.pop(); } llong findMIN() { llong res = INF; if (left.size()) res = std::min(res, left[0]); if (right.size()) res = std::min(res, right.top()); return res; } }; WindowMIN wMin; int solve(int N, int K, int* v) { n = N; k = K; for (int i = 1 ; i <= n ; ++i) { a[i] = v[i - 1]; } a[0] = INTINF; dp[0] = 0; for (int i = 1 ; i <= n ; ++i) { if (dq.size() && dq[0] == i - k) { if (dq.size() >= 2) { fromWhere[dq[1]] = 1; } dq.pop_front(); } while (dq.size() && a[i] > a[dq.back()]) { if (dq.size() >= 2) { fromWhere[dq.back()] = 2; } dq.pop_back(); } dq.push_back(i); } dq.clear(); llong nonPopped = INF; for (int i = 1 ; i <= n ; ++i) { if (i == 250) break; if (dq.size() && dq[0] == i - k) { if (dq.size() >= 2) { wMin.popLeft(); } dq.pop_front(); } while (dq.size() && a[i] > a[dq.back()]) { if (dq.size() >= 2) { wMin.popRight(); } dq.pop_back(); } if (dq.size()) { if (fromWhere[i] == 1) wMin.pushLeft(dp[dq.back()] + a[i]); else if (fromWhere[i] == 2) wMin.pushRight(dp[dq.back()] + a[i]); else nonPopped = std::min(nonPopped, dp[dq.back()] + a[i]); } dq.push_back(i); dp[i] = wMin.findMIN(); dp[i] = std::min(dp[i], nonPopped); dp[i] = std::min(dp[i], dp[std::max(0, i - k)] + a[dq[0]]); } int ans = 0; for (int i = 1 ; i <= n ; ++i) { ans = (1LL * ans * 23 + dp[i]) % MOD; } return ans; }
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