Submission #857096

#TimeUsernameProblemLanguageResultExecution timeMemory
857096alexddNoM (RMI21_nom)C++17
52 / 100
16 ms14940 KiB
#include<bits/stdc++.h> using namespace std; #define int long long const int MOD = 1e9+7; int n,m; int dp[2005][2005]; int cntr[2005]; int pref[2005]; int fact[5005]; int invf[5005]; int put2[5005]; int put(int a, int exp) { if(exp==0) return 1; if(exp%2==0) return put((a*a)%MOD,exp/2); else return (put((a*a)%MOD,exp/2)*a)%MOD; } int comb(int x, int y) { if(x<y) return 0; return ((((fact[x]*invf[y])%MOD)*invf[x-y])%MOD); } signed main() { cin>>n>>m; for(int i=1;i<=2*n;i++) cntr[i%m+1]++; fact[0]=1; put2[0]=1; for(int i=1;i<=5*n;i++) { fact[i]=(fact[i-1]*i)%MOD; put2[i]=(put2[i-1]*2)%MOD; } invf[n*5] = put(fact[n*5], MOD-2); for(int i=n*5-1;i>=0;i--) invf[i]=(invf[i+1]*(i+1))%MOD; dp[0][0]=1; for(int i=1;i<=m;i++) { pref[i]=(pref[i-1]+cntr[i])%MOD; for(int cntp=0;cntp<=pref[i]/2;cntp++) { dp[i][cntp]=0; for(int x=0;x<=min(cntp,cntr[i]);x++) { dp[i][cntp] += (((((dp[i-1][cntp-x] * fact[cntr[i]])%MOD) * comb(pref[i-1] - 2*(cntp-x), x))%MOD) * (put2[cntr[i]-x] * comb(n - (pref[i-1] - 2*(cntp-x) - x) - (cntp-x) - x, cntr[i]-x)%MOD))%MOD; dp[i][cntp] %= MOD; } //cout<<i<<" "<<cntp<<" "<<dp[i][cntp]<<"\n"; } } cout<<dp[m][n]; return 0; } /** dp[i][cntp] = numarul de moduri de a plasa pietre pe primele i resturi a.i. sa fi plasat cntp perechi de pietre cntr[i] = nr de pozitii cu restul i pref[i] = sum(cntr[x]), x = 1..i dp[i][cntp] = sum(dp[i-1][cntp-x] * fact[cntr[i]] * comb(pref[i-1] - 2*cntp, x) * comb(n - (pref[i-1] - 2*cntp - x) - cntp - x, cntr[i]-x) */
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