Submission #856180

#	Time	Username	Problem	Language	Result	Execution time	Memory
856180		sofijavelkovska	Star Trek (CEOI20_startrek)	C++14	30 / 100	1004 ms	9052 KiB

startrek

#include <bits/stdc++.h>
using namespace std;

const int MAXN=1e5, MOD=1e9+7;

vector<int> adj[MAXN+1];
bool win0[MAXN+1], win1[MAXN+1];
int n;

long long power4(long long n)
{
    long long result=1, current=4;
    for (long long i=0; i<64; i++)
    {
        if (n&((long long)1<<i))
            result=result*current%MOD;
        current=current*current%MOD;
    }

    return result;
}

bool dfs0(int x, int t)
{
    bool possible=false;
    for (auto y : adj[x])
    {
        if (y==t)
            continue;
        if (!dfs0(y, x))
            possible=true;
    }

    return win0[x]=possible;
}

bool dfs1(int x, int t)
{
    for (auto y : adj[x])
        if (y!=t && !dfs1(y, x))
            return true;

    return false;
}

int dfscritical(int x, int t)
{
    int critical=0;
    if (!win0[x])
    {
        critical=critical+1;
        for (auto y : adj[x])
        {
            if (y==t)
                continue;
            critical=critical+dfscritical(y, x);
        }
    }
    else
    {
        int losenodes=0;
        for (auto y : adj[x])
        {
            if (y==t)
                continue;
            if (!win0[y])
            {
                critical=critical+dfscritical(y, x);
                losenodes=losenodes+1;
            }
        }
        if (losenodes>1)
            critical=0;
    }

    return critical;
}

int main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);

    int x, y, i;
    long long d, total;
    cin >> n >> d;
    for (i=0; i<n-1; i++)
    {
        cin >> x >> y;
        adj[x].push_back(y);
        adj[y].push_back(x);
    }
    if (n==2)
    {
        cout << power4(d);
        return 0;
    }
    dfs0(1, -1);
    for (i=1; i<=n; i++)
        win1[i]=dfs1(i, -1);
    int win=0;
    for (i=1; i<=n; i++)
        if (win1[i])
            win=win+1;
    int lose=n-win;
    int critical=dfscritical(1, -1);
    /*for (i=1; i<=n; i++)
        cout << win0[i] << " ";
    cout << '\n';
    for (i=1; i<=n; i++)
        cout << win1[i] << " ";
    cout << '\n';*/
    //cout << win << " " << lose << " " << critical << '\n';
    if (win0[1])
        total=n*win+(n-critical)*lose;
    else
        total=critical*lose;

    cout << total;

    return 0;
}

• Subtask 1: 0 / 0
• Subtask 2: 7 / 7
• Subtask 3: 8 / 8
• Subtask 4: 15 / 15
• Subtask 5: 0 / 15
• Subtask 6: 0 / 20
• Subtask 7: 0 / 20
• Subtask 8: 0 / 15