Submission #855980

#TimeUsernameProblemLanguageResultExecution timeMemory
855980RiverFlow Martian DNA (BOI18_dna)C++14
0 / 100
101 ms141616 KiB
#include <bits/stdc++.h> #define nl "\n" #define no "NO" #define yes "YES" #define fi first #define se second #define vec vector #define task "main" #define _mp make_pair #define ii pair<int, int> #define sz(x) (int)x.size() #define all(x) x.begin(), x.end() #define evoid(val) return void(std::cout << val) #define FOR(i, a, b) for(int i = (a); i <= (b); ++i) #define FOD(i, b, a) for(int i = (b); i >= (a); --i) #define unq(x) sort(all(x)); x.resize(unique(all(x)) - x.begin()) using namespace std; template<typename U, typename V> bool maxi(U &a, V b) { if (a < b) { a = b; return 1; } return 0; } template<typename U, typename V> bool mini(U &a, V b) { if (a > b) { a = b; return 1; } return 0; } const int N = (int)2e5 + 9; const int mod = (int)1e9 + 7; void prepare(); void main_code(); int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); if (fopen(task".inp", "r")) { freopen(task".inp", "r", stdin); freopen(task".out", "w", stdout); } const bool MULTITEST = 0; prepare(); int num_test = 1; if (MULTITEST) cin >> num_test; while (num_test--) { main_code(); } } void prepare() {}; int a[N], cnt[12][N], b[N], q[N], ind[N]; int n, k, r; bool check(int x, int y) { FOR(i, 1, r) if (cnt[i][y] - cnt[i][x - 1] < q[i]) return 0; return 1; } void subtask3() { FOR(j, 1, r) { FOR(i, 1, n) cnt[j][i] = cnt[j][i - 1] + (a[i] == j); } int res = n + 1, j = 1; FOR(i, 1, n) { while (j <= i and check(j, i)) { res = min(res, i - j + 1); ++j; } } if (res == n + 1) evoid("impossible"); cout << res; } int c[N]; queue<int> pos[N]; bool ok[N]; void main_code() { cin >> n >> k >> r; FOR(i, 1, n) cin >> a[i], ++a[i]; FOR(i, 1, r) cin >> b[i] >> q[i], ++b[i]; FOR(i, 1, r) ind[b[i]] = i; ind[0] = 0; FOR(i, 1, n) a[i] = ind[ a[i] ]; // if (r <= 10) return subtask3(), void(); int j = 1, d = 0, ans = n + 1; FOR(i, 1, n) { int v = a[i]; if (v == 0) continue ; pos[v].push(i); d -= ok[v]; ok[v] |= sz(pos[v]) == q[v]; d += ok[v]; while (sz(pos[v]) > q[v] and pos[v].front() == j) { pos[v].pop(); ++j; while (j <= i and a[j] == 0) ++j; } if (d == r) { ans = min(ans, i - j + 1); } } if (ans == n + 1) evoid("impossible"); cout << ans; } /* Let the river flows naturally */

Compilation message (stderr)

dna.cpp: In function 'void main_code()':
dna.cpp:15:22: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   15 | #define FOR(i, a, b) for(int i = (a); i <= (b); ++i)
      |                      ^~~
dna.cpp:83:5: note: in expansion of macro 'FOR'
   83 |     FOR(i, 1, r) ind[b[i]] = i; ind[0] = 0;
      |     ^~~
dna.cpp:83:33: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   83 |     FOR(i, 1, r) ind[b[i]] = i; ind[0] = 0;
      |                                 ^~~
dna.cpp: In function 'int main()':
dna.cpp:36:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   36 |         freopen(task".inp", "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
dna.cpp:37:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   37 |         freopen(task".out", "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
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