This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define fast ios::sync_with_stdio(0);cin.tie(0);
#define s second
#define f first
typedef long long ll;
const ll MOD = 998244353;
const ll LOGN = 20;
const ll MAXN = 1e5 + 5;
const int BLOCK = 500;
struct Query {
int A, B, C, idx;
bool operator< (Query y) {
return make_pair(A / BLOCK, B) < make_pair(y.A / BLOCK, y.B);
}
};
vector<Query> Q;
int fen[MAXN], ans[MAXN], sumCoor[MAXN];
vector<int> S, T, cc;
vector<pair<int,int>> tt, ss;
map<int,int> cnt;
void update(int k, int val) {
k++;
while (k < MAXN) {
fen[k] += val;
k += k & -k;
}
}
int get(int k) {
k++;
int res = 0;
while (k >= 1) {
res += fen[k];
k -= k & -k;
}
return res;
}
int main() {
fast
int N, Qs;
cin >> N >> Qs;
S = vector<int>(N);
T = vector<int>(N);
for (int i = 0; i < N; i++) {
cin >> S[i] >> T[i];
ss.push_back({S[i], i});
tt.push_back({T[i], i});
cc.push_back(S[i] + T[i]);
}
sort(cc.begin(), cc.end());
sort(ss.begin(), ss.end());
sort(tt.begin(), tt.end());
for (int i = 0; i < N; i++)
sumCoor[i] = lower_bound(cc.begin(), cc.end(), S[i] + T[i]) - cc.begin();
for (int i = 0; i < Qs; i++) {
Query q;
cin >> q.A >> q.B >> q.C;
q.A = lower_bound(ss.begin(), ss.end(), make_pair(q.A, 0)) - ss.begin();
q.B = lower_bound(tt.begin(), tt.end(), make_pair(q.B, 0)) - tt.begin();
q.C = lower_bound(cc.begin(), cc.end(), q.C) - cc.begin();
q.idx = i;
Q.push_back(q);
}
sort(Q.begin(), Q.end());
int s = N; // tamamen sağda
int t = N;
for (auto u : Q) {
int new_s = u.A;
int new_t = u.B;
while (new_s < s) {
cnt[ss[s-1].s]++;
if (cnt[ss[s-1].s] == 2)
update(sumCoor[ss[s-1].s], 1);
s--;
}
while (new_t < t) {
cnt[tt[t-1].s]++;
if (cnt[tt[t-1].s] == 2)
update(sumCoor[tt[t-1].s], 1);
t--;
}
while (new_s > s) {
cnt[ss[s].s]--;
if (cnt[ss[s].s] == 1)
update(sumCoor[ss[s].s], -1);
s++;
}
while (new_t > t) {
cnt[tt[t].s]--;
if (cnt[tt[t].s] == 1)
update(sumCoor[tt[t].s], -1);
t++;
}
ans[u.idx] = get(MAXN - 2) - get(u.C - 1);
}
for (int i = 0; i < Qs; i++)
cout << ans[i] << "\n";
}
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