Submission #851371

#	Time	Username	Problem	Language	Result	Execution time	Memory
851371		NotLinux	Volontiranje (COCI21_volontiranje)	C++17	0 / 110	1034 ms	344 KiB

Main

#include <bits/stdc++.h>
using namespace std;
struct SEGT{//range max , point update
	vector < int > tree;
	int sz;
	SEGT(int x){
		x++;
		sz = x;
		tree.assign(4*x,0);
	}
	void _update(int ind , int l , int r , int qp , int qv){
		if(l == r){
			tree[ind] = qv;
			return;
		}
		int mid = (l+r)/2;
		if(mid >= qp){
			_update(ind*2,l,mid,qp,qv);
		}
		else {
			_update(ind*2+1,mid+1,r,qp,qv);
		}
		tree[ind] = max(tree[ind*2] , tree[ind*2+1]);
	}
	void update(int p , int v){
		_update(1,1,sz,p,v);
	}
	int _query(int ind , int l , int r , int ql , int qr){
		if(l >= ql and r <= qr){
			return tree[ind];
		}
		else if(l > qr or r < ql){
			return 0;
		}
		else{
			int mid = (l+r)/2;
			return max(_query(ind*2,l,mid,ql,qr) , _query(ind*2+1,mid+1,r,ql,qr));
		}
	}
	int query(int l , int r){
		return _query(1,1,sz,l,r);
	}

};
void solve(){
	int n;
	cin >> n;
	SEGT segt(n+1);
	int p[n],lis[n],mx = 1;
	for(int i = 0;i<n;i++){
		cin >> p[i];
		lis[i] = 1 + segt.query(1,p[i]);
		segt.update(p[i] , lis[i]);
		mx = max(mx , lis[i]);
	}
	set < pair < int , int > > v[mx+2];
	vector < int > starting_points;
	int go[n];
	memset(go , -1 , sizeof(go));
	for(int i = n-1;i>=0;i--){
		if(v[lis[i]+1].size()){
			go[i] = (*v[lis[i]+1].begin()).second;
			v[lis[i+1]].erase(v[lis[i+1]].begin());
			v[lis[i]].insert({p[i],i});
			if(lis[i] == 1){
				starting_points.push_back(i);
			}
		}
		else if(lis[i] == mx){
			v[lis[i]].insert({p[i],i});
			if(lis[i] == 1){
				starting_points.push_back(i);
			}
		}
	}
	cout << starting_points.size() << " " << mx << endl;
	for(auto itr : starting_points){
		int cur = itr;
		do{
			cout << cur+1 << " ";
			cur = go[cur];
		}while(cur != -1);
		cout << '\n';
	}
}
signed main(){
	ios_base::sync_with_stdio(0);cin.tie(0);
	int testcase = 1;//cin >> testcase;
	while(testcase--)solve();
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 40
• Subtask 3: 0 / 60