Submission #849666

#	Time	Username	Problem	Language	Result	Execution time	Memory
849666		adhityamv	Sequence (APIO23_sequence)	C++17	0 / 100	2009 ms	60420 KiB

sequence

#include <bits/stdc++.h>
using namespace std;
int sequence(int n,vector<int> A){
    int x=0;
    int a[n];
    int b[n];
    int cnt[n]={};
    vector<int> ind[n];
    for(int i=0;i<n;i++){
        A[i]--;
        cnt[A[i]]++;
        if(A[i]>0) a[i]=-1;
        else a[i]=1;
        if(A[i]<0) b[i]=-1;
        else b[i]=1;
        ind[A[i]].push_back(i);
    }
    int ans=0;
    while(x<n){
        if(cnt[x]!=0){
            int spa[2*n+1];
            int epa[2*n+1];
            for(int i=0;i<=2*n;i++){
                spa[i]=-1;
                epa[i]=-1;
            }
            int spb[2*n+1];
            int epb[2*n+1];
            for(int i=0;i<=2*n;i++){
                spb[i]=-1;
                epb[i]=-1;
            }
            int prefixa[n+1];
            int prefixb[n+1];
            int cva=0;
            int cvb=0;
            for(int i=0;i<=n;i++){
                if(spa[cva+n]==-1) spa[cva+n]=i;
                if(spb[cvb+n]==-1) spb[cvb+n]=i;
                epa[cva+n]=i;
                epb[cvb+n]=i;
                prefixa[i]=cva;
                prefixb[i]=cvb;
                if(i<n){
                    cva+=a[i];
                    cvb+=b[i];
                }
            }
            for(int i=0;i<=2*n;i++){
                if(spa[i]!=-1){
                    ans=max(ans,prefixb[epa[i]]-prefixb[spa[i]]);
                }
                if(spb[i]!=-1){
                    ans=max(ans,prefixa[epb[i]]-prefixa[spb[i]]);
                }
                if(i>0)if(prefixa[i]<=prefixa[n] && prefixb[i]<=prefixb[n]){
                    ans=max(ans,prefixb[n]+prefixa[n]-prefixb[i]-prefixa[i]);
                }
            }
        }
        if(x+1<n){
            for(int i:ind[x]){
                b[i]=-1;
            }
            for(int i:ind[x+1]){
                a[i]=1;
            }
        }
        x++;
    }
    return ans/2;
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 17
• Subtask 3: 0 / 7
• Subtask 4: 0 / 12
• Subtask 5: 0 / 13
• Subtask 6: 0 / 22
• Subtask 7: 0 / 18