Submission #847980

#	Time	Username	Problem	Language	Result	Execution time	Memory
847980		resting	Modern Machine (JOI23_ho_t5)	C++17	25 / 100	3045 ms	578280 KiB

Main

#include <bits/stdc++.h>
using namespace std;

#define int long long
const int mx = 1.2e5 + 5;

const int magic = 350;
//const int magic = 3;

namespace rmq {
    struct segtree {
        segtree* lc = 0, * rc = 0;
        int l, r;
        int v = numeric_limits<int>::max();
        segtree* getmem();
        segtree() : segtree(-1, -1) {};
        segtree(int l, int r) : l(l), r(r) {
            if (l == r)return;
            int m = (l + r) / 2;
            lc = getmem(); *lc = segtree(l, m);
            rc = getmem(); *rc = segtree(m + 1, r);
        };
        segtree* upd(int qi, int qv) {
            segtree* tr = getmem(); *tr = *this;
            if (qi < l || qi > r) return tr;
            if (l == r) { tr->v = qv; return tr; }
            tr->lc = lc->upd(qi, qv); tr->rc = rc->upd(qi, qv);
            tr->v = min(tr->lc->v, tr->rc->v);
            return tr;
        }
        int q(int ql, int qr) {
            if (ql > qr)return numeric_limits<int>::max();
            if (ql > r || qr < l) return numeric_limits<int>::max();
            if (ql <= l && qr >= r) return v;
            return min(lc->q(ql, qr), rc->q(ql, qr));
        }
    }mem[mx * 40]; int memsz = 0;// surely enogh?
    segtree* segtree::getmem() { return &mem[memsz++]; }
}

namespace rsq {
    struct segtree {
        segtree* lc = 0, * rc = 0;
        int l, r;
        int v = 0;
        segtree* getmem();
        segtree() : segtree(-1, -1) {};
        segtree(int l, int r) : l(l), r(r) {
            if (l == r)return;
            int m = (l + r) / 2;
            lc = getmem(); *lc = segtree(l, m);
            rc = getmem(); *rc = segtree(m + 1, r);
        };
        segtree* upd(int qi, int qv) {
            segtree* tr = getmem(); *tr = *this;
            if (qi < l || qi > r) return tr;
            if (l == r) { tr->v += qv; return tr; }
            tr->lc = lc->upd(qi, qv); tr->rc = rc->upd(qi, qv);
            tr->v = tr->lc->v + tr->rc->v;
            return tr;
        }
        int q(int ql, int qr) {
            if (ql > qr) return 0;
            if (ql > r || qr < l) return 0;
            if (ql <= l && qr >= r) return v;
            return lc->q(ql, qr) + rc->q(ql, qr);
        }
    }mem[mx * 80]; int memsz = 0;// surely enogh?
    segtree* segtree::getmem() { return &mem[memsz++]; }
}

struct bit {
    vector<int> b, a;
    bit(int n) : b(n + 1, 0), a(n + 1, 0) {};
    int q(int i) { int v = 0; for (i++; i > 0; i -= i & -i) v += b[i]; return v; }
    void u(int i, int v) { if (i < a.size()) a[i] += v; for (i++; i < b.size(); i += i & -i) b[i] += v; }
    void u(int l, int r, int v) { if (l > r) return; u(l, v);  u(r + 1, -v); }
};

int holy[mx / magic][mx];


int32_t main() {
    cin.tie(0)->sync_with_stdio(0);
    int n, m; cin >> n >> m;
    string c; cin >> c;
    vector<int> a(m); for (auto& x : a) { cin >> x;  x--; }
    vector<vector<int>> a2(n + 1);
    for (int i = 0; i < m; i++) a2[a[i]].push_back(i);
    vector<int> ls, rs;
    ls.push_back(-1); rs.push_back(n);
    for (int i = 0; i < n; i++) if (c[i] == 'B') ls.push_back(i);
    for (int i = n - 1; i >= 0; i--) if (c[i] == 'R') rs.push_back(i);

    vector<int> pre(n, 0);
    for (int i = 0; i < n; i++) {
        if (i) pre[i] = pre[i - 1];
        pre[i] += c[i] == 'R';
    }

    auto sm = [&](int l, int r) {
        if (l > r) return 0LL;
        if (l > n) l = n;
        if (r > n - 1) r = n - 1;
        if (r < 0) return 0LL;
        if (l <= 0) return pre[r];
        return pre[r] - pre[l - 1];
    }; //very necessary yk

    rmq::segtree* tmp = new rmq::segtree(0, n - 1);
    vector<rmq::segtree*> ac(m, 0);
    for (int i = m - 1; i >= 0; i--) {
        ac[i] = tmp = tmp->upd(a[i], i);
    }

    rsq::segtree* tmp2 = new rsq::segtree(0, m - 1);
    vector<rsq::segtree*> ac2(n + 1, 0);
    for (int i = 0; i <= n; i++) {
        for (auto& x : a2[i]) tmp2 = tmp2->upd(x, i + 1);
        ac2[i] = tmp2;
    }

    rsq::segtree* tmp3 = new rsq::segtree(0, m - 1);
    vector<rsq::segtree*> ac3(n + 1, 0);
    for (int i = n; i >= 0; i--) {
        for (auto& x : a2[i]) {
            tmp3 = tmp3->upd(x, n - 1 - i);
        }
        ac3[i] = tmp3;
    }

    bit die(n + 1);
    for (int j = 0; j + magic <= m; j += magic) {
        int k = j / magic;
        die.a.assign(n + 2, 0);
        die.b.assign(n + 2, 0);
        for (int i = 0; i <= n; i++) die.u(i, i, i);
        for (int x = j; x < j + magic; x++) {
            int cur = 0;
            while (cur <= n) {
                int i = die.q(cur) / (n + 1);
                int l = cur - 1, r = n + 1;
                while (r - l > 1) {
                    int m = l + (r - l) / 2;
                    if (die.q(m) / (n + 1) == i) l = m;
                    else r = m;
                }
                //[cur, l] is bound
                int l2 = cur - 1, r2 = l + 1;
                while (r2 - l2 > 1) {
                    int m = l2 + (r2 - l2) / 2;
                    if (die.q(m) % (n + 1) <= a[x]) l2 = m;
                    else r2 = m;
                }
                //r is bound
                die.u(cur, l2, 1);
                cur = l + 1;
            }
            die.u(0, n, a[x] + 1);
        }
        // for (int i = 0; i <= n; i++) {
        //     if (i) die.a[i] += die.a[i - 1];
        //     holy[k][i] = die.a[i] % (n + 1);
        // }
    }

    int q; cin >> q;

    while (q--) {
        int l, r; cin >> l >> r; l--;r--;
        //solve
        int li = -1, ri = n;
        int cur = l;
        auto qcnt = [&](int l, int r) {
            int res = 0;
            if (l > r) return 0LL;
            if (r <= li) return r - l + 1;
            if (l >= ri) return 0LL;
            if (l <= li) {
                res += li - l + 1;
                l = li + 1;
            }
            if (r >= ri) r = ri - 1;
            return res + sm(l, r);
            //LMAO
        };

        auto qcnt2 = [&](int l, int r) {
            if (l > r) return 0LL;
            return (r - l + 1) - qcnt(l, r);};

        auto thing = [&](int t) { // should work for everything?
            int a = qcnt(0, t - 1) * 2 + 1;
            int b = qcnt2(t + 1, n - 1) * 2;
            if (a > b) {
                int ll = 0 - 1, rr = t + 1;
                while (rr - ll > 1) {
                    int m = ll + (rr - ll) / 2;
                    if (qcnt(m, t - 1) * 2 + 1 >= b)ll = m;
                    else rr = m;
                }
                ri = min(ri, ll);
                if (li >= ri) li = ri - 1;
            } else {
                int ll = t, rr = n;
                while (rr - ll > 1) {
                    int m = ll + (rr - ll) / 2;
                    if (qcnt2(t + 1, m) * 2 >= a)rr = m;
                    else ll = m;
                }
                li = rr;
                if (ri <= li) ri = li + 1;
            }
        };

        auto test = [&](int t) -> bool {
            int v1 = li == -1 ? 0 : ac2[li]->q(cur, t);
            int v2 = ri == n ? 0 : ac3[ri]->q(cur, t);
            int tmp1 = prev(upper_bound(ls.begin(), ls.end(), li)) - ls.begin();
            int tmp2 = prev(upper_bound(rs.begin(), rs.end(), ri, greater<int>())) - rs.begin();
            if (tmp1 + v1 >= ls.size()) return false;
            if (tmp2 + v2 >= rs.size()) return false;
            int nl = v1 ? ls[tmp1 + v1] : li;
            int nr = v2 ? rs[tmp2 + v2] : ri;
            if (nl >= nr) return false;
            li = nl; ri = nr;
            cur = t + 1;
            return true;
        };

        while (cur <= r) {
            int t = min(ac[cur]->q(li + 1, ri - 1), r + 1);
            //do the thing?
            if (!test(t - 1)) break;
            if (cur <= r)thing(a[cur++]);
        }
        if (cur <= r) {
            int t = min(ac[cur]->q(li + 1, ri - 1), r + 1);
            for (int i = 18; i >= 0; i--) {
                if (cur + (1 << i) <= t - 1) test(cur + (1 << i));
            }
        }

        for (int i = 0; i < 5; i++) if (cur <= r) thing(a[cur++]);
        while (cur <= r) {
            if (0 && cur % magic == 0 && cur + magic <= r + 1) {
                ri = holy[cur / magic][ri];
                li = ri - 1;
                cur += magic;
            } else {
                if (a[cur] >= ri) ri++;
                ri += a[cur] + 1;
                while (ri >= n + 1) ri -= (n + 1);
                li = ri - 1;
                cur++;
            }
        }
        cout << qcnt(0, n - 1) << endl;
    }
}

Compilation message (stderr)

Main.cpp: In member function 'void bit::u(long long int, long long int)':
Main.cpp:76:34: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   76 |     void u(int i, int v) { if (i < a.size()) a[i] += v; for (i++; i < b.size(); i += i & -i) b[i] += v; }
      |                                ~~^~~~~~~~~~
Main.cpp:76:69: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   76 |     void u(int i, int v) { if (i < a.size()) a[i] += v; for (i++; i < b.size(); i += i & -i) b[i] += v; }
      |                                                                   ~~^~~~~~~~~~
Main.cpp: In function 'int32_t main()':
Main.cpp:134:13: warning: unused variable 'k' [-Wunused-variable]
  134 |         int k = j / magic;
      |             ^
Main.cpp: In lambda function:
Main.cpp:221:27: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  221 |             if (tmp1 + v1 >= ls.size()) return false;
      |                 ~~~~~~~~~~^~~~~~~~~~~~
Main.cpp:222:27: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  222 |             if (tmp2 + v2 >= rs.size()) return false;
      |                 ~~~~~~~~~~^~~~~~~~~~~~

• Subtask 1: 3 / 3
• Subtask 2: 12 / 12
• Subtask 3: 10 / 10
• Subtask 4: 0 / 11
• Subtask 5: 0 / 26
• Subtask 6: 0 / 17
• Subtask 7: 0 / 21