Submission #846952

#	Time	Username	Problem	Language	Result	Execution time	Memory
846952		SUNWOOOOOOOO	Financial Report (JOI21_financial)	C++17	14 / 100	348 ms	779600 KiB

Main

#include <bits/stdc++.h>
using namespace std;
const int mxN = 7005;
int n, d, A[mxN], dp1[mxN][mxN], dp2[mxN][mxN]; // len, last idx
vector <int> va;

int main()
{
    memset(dp1, -1, sizeof dp1);
    memset(dp2, -1, sizeof dp2);
    scanf("%d %d", &n, &d);
    for (int i = 1; i <= n; i++) {
        scanf("%d", &A[i]);
        va.push_back(A[i]);
    }
    sort(va.begin(), va.end());
    va.erase(unique(va.begin(), va.end()), va.end());
    for (int i = 1; i <= n; i++) A[i] = lower_bound(va.begin(), va.end(), A[i]) - va.begin() + 1;

    int ans = 0;
    for (int i = 1; i <= n; i++){
        dp1[i][A[i]] = 1, dp2[i][A[i]] = i;
        if (dp1[i - 1][A[i]] != -1 && i - dp2[i - 1][A[i]] <= d) dp1[i][A[i]] = dp1[i - 1][A[i]];
        for (int j = 1; j < A[i]; j++){
            if (dp1[i - 1][j] == -1 || i - dp2[i - 1][j] > d) continue;
            dp1[i][j] = dp1[i - 1][j], dp2[i][j] = dp2[i - 1][j];
            dp1[i][A[i]] = max(dp1[i][A[i]], dp1[i - 1][j] + 1);
        }
        for (int j = A[i] + 1; j <= n; j++){
            if (dp1[i - 1][j] == -1) continue;
            dp1[i][j] = dp1[i - 1][j];
            dp2[i][j] = i;
        }
        for (int j = 1; j <= n; j++) ans = max(ans, dp1[i][j]);
    }

    printf("%d\n", ans);

    return 0;
}

Compilation message (stderr)

Main.cpp: In function 'int main()':
Main.cpp:11:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   11 |     scanf("%d %d", &n, &d);
      |     ~~~~~^~~~~~~~~~~~~~~~~
Main.cpp:13:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   13 |         scanf("%d", &A[i]);
      |         ~~~~~^~~~~~~~~~~~~

• Subtask 1: 14 / 14
• Subtask 2: 0 / 14
• Subtask 3: 0 / 20
• Subtask 4: 0 / 12
• Subtask 5: 0 / 5
• Subtask 6: 0 / 35