Submission #839494

#	Time	Username	Problem	Language	Result	Execution time	Memory
839494		Lilinta	Type Printer (IOI08_printer)	C++14	100 / 100	122 ms	106424 KiB

printer

// IOI 2008 Day 1 Problem 1 - Type Printer
// Problem link: https://oj.uz/problem/view/IOI08_printer
#include <bits/stdc++.h>
using namespace std;

struct Trie {
    struct Node {
        Node* child[26];
        bool exist = false;
        int maxDepth = 0;
        int deepest = -1;

        Node() {
            for (int c = 0; c < 26; ++c) {
                child[c] = nullptr;
            }
        }
    };

    Node* root;

    Trie() {
        root = new Node();
    }

    void addString(string &s) {
        Node* p = root;
        int n = s.size();
        for (int i = 0; i < n; ++i) {
            int c = s[i] - 'a';
            if (!(p -> child[c])) {
                p -> child[c] = new Node();
            }
            if (n - i > p -> maxDepth) {
                p -> maxDepth = n - i;
                p -> deepest = c;
            }
            p = p -> child[c];
        }
        p -> exist = true;
    }
    /*
    void selfDelete(Node* p) {
        for (int c = 0; c < 26; ++c) {
            if (p -> child[c]) {
                selfDelete(p -> child[c]);
            }
        }
        delete p;
    }
    */
};

int n;
Trie T;
vector<char> output;

void dfs(Trie::Node* p) {
    if (p -> exist) {
        output.push_back('P');
    }
    for (int c = 0; c < 26; ++c) {
        if (c != p -> deepest && p -> child[c]) {
            output.push_back(c + 'a');
            dfs(p -> child[c]);
            output.push_back('-');
        }
    }
    if (p -> deepest != -1) {
        output.push_back(p -> deepest + 'a');
        dfs(p -> child[p -> deepest]);
        output.push_back('-');
    }
    delete p;
}

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    cin >> n;
    for (int i = 0; i < n; ++i) {
        string s;
        cin >> s;
        T.addString(s);
    }
    dfs(T.root);
    while (output.back() == '-') {
        output.pop_back();
    }
    cout << output.size() << '\n';
    for (char c : output) {
        cout << c << '\n';
    }
    return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 10 / 10
• Subtask 5: 10 / 10
• Subtask 6: 10 / 10
• Subtask 7: 10 / 10
• Subtask 8: 10 / 10
• Subtask 9: 10 / 10
• Subtask 10: 10 / 10