This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
class segment_tree{
public:
int tree[1048576 * 2] = {0};
int N = 1048576;
void update(int head, int l, int r, int pos, int val){
if(r - l == 1){
tree[head] += val;
return;
}
int mid = (l + r) / 2;
if(pos < mid){
update(head * 2 + 1, l, mid, pos, val);
}
else{
update(head *2 + 2, mid, r, pos, val);
}
tree[head] = max(tree[head * 2 + 2], tree[head * 2 + 1]);
}
void update(int pos, int val){
update(0, 0, N, pos, val);
}
};
int arr[1000050];
int main(){
int N, M;
cin >> N >> M;
for(int i = 0; i < N; i ++){
cin >> arr[i];
arr[i]--;
}
segment_tree tree;
vector<vector<vector<int>>> brr(M + 5, vector<vector<int>>(2));
vector<int> counts(M + 5);
for(int i = 0; i < N; i ++){
for(int j = 0; j < 2; j ++){
int pi = i + 1 - (i + j) % 2 * 2;
if(pi > -1 && pi < N && arr[pi] != arr[i]){
brr[arr[i]][j].push_back(arr[pi]);
}
}
counts[arr[i]] ++;
tree.update(arr[i], 1);
}
for(int i = 0; i < M; i ++){
tree.update(i, -counts[i]);
int ans = N;
for(int j = 0; j < 2; j ++){
for(int &k : brr[i][j])tree.update(k, -1);
ans = min(ans, N-tree.tree[0]-counts[i]);
for(int &k : brr[i][j])tree.update(k, 1);
}
tree.update(i, counts[i]);
cout << ans << '\n';
}
}
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