Submission #837095

#TimeUsernameProblemLanguageResultExecution timeMemory
837095erdemkirazAliens (IOI16_aliens)C++17
25 / 100
2048 ms22228 KiB
#include "aliens.h" #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> ii; const int M = 1e6 + 5; int n, m, k; int at[M]; vector<int> ats; vector<ii> v; vector<vector<ll>> dp; // ll f(int x, int last, int k) { // if(x >= m) { // return 0; // } // ll &r = dp[x][last][k]; // if(r != -1) { // return r; // } // r = 1e18; // if(ats[last] >= ats[v[x].second]) { // r = min(r, f(x + 1, last, k)); // } // if(k) { // // int mx = 0; // // for(int y = x; y < m; y++) { // // mx = max(mx, v[y].second); // // if(ats[mx] <= ats[last]) { // // continue; // // } // // ll len = ats[mx] - v[x].first; // // ll prev_len = max(0, ats[last] - v[x].first); // // r = min(r, f(x + 1, mx, k - 1) + len * len - prev_len * prev_len); // // } // int mx = 0; // int y = last + 1; // if(ats[v[x].second] > ats[last]) { // y = v[x].second; // } // for(; y < (int) ats.size(); y++) { // ll len = ats[y] - v[x].first; // ll prev_len = max(0, ats[last] - v[x].first); // r = min(r, f(x + 1, y, k - 1) + len * len - prev_len * prev_len); // } // } // // printf("x = %d last = %d k = %d r = %lld\n", x, last, k, r); // return r; // } ll take_photos(int nn, int mm, int kk, vector<int> r, vector<int> c) { n = nn; m = mm; k = kk; for(int i = 0; i < n; i++) { if(r[i] > c[i]) { swap(r[i], c[i]); } at[r[i] + 1] = max(at[r[i] + 1], c[i] + 2); } v.push_back({0, 0}); for(int i = 1; i <= m + 1; i++) { if(at[i]) { if(!ats.empty() and ats.back() >= at[i]) { continue; } ats.push_back(at[i]); v.push_back({i, at[i]}); } } // ats.push_back(0); // sort(ats.begin(), ats.end()); // ats.resize(unique(ats.begin(), ats.end()) - ats.begin()); // for(auto& [x, y] : v) { // y = lower_bound(ats.begin(), ats.end(), y) - ats.begin(); // } m = (int) v.size() - 1; dp.resize(m + 1, vector<ll>(k + 1, 1e18)); for(int i = 0; i <= k; i++) { dp[0][i] = 0; } for(int j = 1; j <= m; j++) { for(int rem = k; rem >= 1; rem--) { for(int i = j; i >= 1; i--) { int prev = v[i - 1].second; int x = v[i].first; int y = v[j].second; ll len = y - x; ll inter = max(0, prev - x); dp[j][rem] = min(dp[j][rem], dp[i - 1][rem - 1] + len * len - inter * inter); } } } ll ans = dp[m][k]; return ans; }
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