Submission #834912

#TimeUsernameProblemLanguageResultExecution timeMemory
834912maomao90Remittance (JOI19_remittance)C++17
100 / 100
245 ms44236 KiB
// Hallelujah, praise the one who set me free // Hallelujah, death has lost its grip on me // You have broken every chain, There's salvation in your name // Jesus Christ, my living hope #include <bits/stdc++.h> using namespace std; #define REP(i, s, e) for (int i = (s); i < (e); i++) #define RREP(i, s, e) for (int i = (s); i >= (e); i--) template <class T> inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;} template <class T> inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;} typedef unsigned long long ull; typedef long long ll; typedef long double ld; #define FI first #define SE second typedef pair<int, int> ii; typedef pair<ll, ll> pll; typedef tuple<int, int, int> iii; #define ALL(_a) _a.begin(), _a.end() #define SZ(_a) (int) _a.size() #define pb push_back typedef vector<int> vi; typedef vector<ll> vll; typedef vector<ii> vii; typedef vector<iii> viii; #ifndef DEBUG #define cerr if (0) cerr #endif const int INF = 1000000005; const ll LINF = 1000000000000000005ll; const int MAXN = 1000005; const ll MOD = 998244353998244393; #define submod(x) if (x >= MOD) x -= MOD int n; ll a[MAXN], b[MAXN], x[MAXN]; ll fpow(__int128 b, ll p) { __int128 res = 1; while (p) { if (p & 1) { res = res * b % MOD; } b = b * b % MOD; p >>= 1; } return res; } int main() { #ifndef DEBUG ios::sync_with_stdio(0), cin.tie(0); #endif cin >> n; ll mxa = 0, smb = 0; REP (i, 0, n) { cin >> a[i] >> b[i]; mxto(mxa, a[i]); smb += b[i]; } bool bad = 0; REP (i, 0, n) { if (a[i] != b[i]) { bad = 1; break; } } if (!bad) { cout << "Yes\n"; return 0; } if (mxa <= 1 || smb == 0) { cout << "No\n"; return 0; } ll pw = 1; REP (i, 0, n) { x[n - 1] += (__int128) (b[i] - a[i] + MOD) * pw % MOD; submod(x[n - 1]); pw = pw * 2; submod(pw); } x[n - 1] = (__int128) x[n - 1] * fpow((-pw + 1 + MOD) % MOD, MOD - 2) % MOD; REP (i, 0, n - 1) { int prv = i - 1; if (prv < 0) { prv += n; } x[i] = a[i] - b[i] + x[prv]; if (x[i] % 2 != 0 || x[i] < 0) { cout << "No\n"; return 0; } x[i] /= 2; } REP (i, 0, n) { int prv = i - 1; if (prv < 0) { prv += n; } if (a[i] - 2 * x[i] + x[prv] != b[i]) { cout << "No\n"; return 0; } } cout << "Yes\n"; return 0; }
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