# |
Submission time |
Handle |
Problem |
Language |
Result |
Execution time |
Memory |
83309 |
2018-11-06T22:15:07 Z |
fredbr |
Cover (COCI18_cover) |
C++17 |
|
5 ms |
852 KB |
#include <bits/stdc++.h>
#define ff first
#define ss second
using namespace std;
// o resultado pode ultrapassar o inteiro normal
typedef long long ll;
typedef pair<ll, ll> ii;
const int maxn = 5010;
ii v[maxn];
ii d[maxn];
ll dp[maxn];
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> v[i].ff >> v[i].ss;
// tratamos somente com o primeiro quadrante
v[i].ff = abs(v[i].ff);
v[i].ss = abs(v[i].ss);
}
sort(v+1, v+n+1);
// ponteiro para o ultimo elemento processado
int cur = 0;
for (int i = 1; i <= n; i++) {
// remove o elemento anterior caso irrelevante
while (cur > 0 and v[i].ss >= d[cur].ss) cur--;
// coloca o elemento atual
d[++cur] = v[i];
}
// lembrar de recontar o numero de elementos
n = cur;
// torna dp[i] infinito para todo i != 0
memset(dp, 0x3f, maxn*8);
dp[0] = 0ll;
// loop que calcula a dp para todos os i
for (int i = 1; i <= n; i++) {
// loop para calcular o dp[i]
for (int j = 0; j < i; j++) {
dp[i] = min(dp[i], dp[j] + d[j+1].ss*d[i].ff);
}
}
cout << dp[n]*4ll << "\n";
return 0;
}
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
2 ms |
376 KB |
Output is correct |
2 |
Correct |
2 ms |
512 KB |
Output is correct |
3 |
Correct |
2 ms |
512 KB |
Output is correct |
4 |
Correct |
2 ms |
512 KB |
Output is correct |
5 |
Correct |
2 ms |
512 KB |
Output is correct |
6 |
Correct |
2 ms |
636 KB |
Output is correct |
7 |
Correct |
2 ms |
636 KB |
Output is correct |
8 |
Correct |
2 ms |
792 KB |
Output is correct |
9 |
Correct |
3 ms |
792 KB |
Output is correct |
10 |
Correct |
5 ms |
852 KB |
Output is correct |