Submission #831863

#	Time	Username	Problem	Language	Result	Execution time	Memory
831863		WLZ	Garden (JOI23_garden)	C++17	0 / 100	188 ms	8056 KiB

garden

#include <bits/stdc++.h>
using namespace std;

const int INF = 0x3f3f3f3f;

int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  int n, m, d; cin >> n >> m >> d;
  vector<int> p(n), q(n), r(m), s(m);
  for (int i = 0; i < n; i++) cin >> p[i] >> q[i];
  for (int i = 0; i < m; i++) cin >> r[i] >> s[i];
  vector<bool> type_1(d, false);
  for (int i = 0; i < n; i++) type_1[q[i]] = true;
  vector<int> last(d, -1);
  for (int i = 0; i < m; i++) if (!type_1[s[i]]) last[s[i]] = max(last[s[i]], r[i]);
  vector< set<int> > type_2(d, set<int>());
  for (int i = 0; i < d; i++) if (last[i] != -1) type_2[last[i]].insert(i);
  vector< vector<int> > by_r(d);
  for (int i = 0; i < m; i++) by_r[r[i]].push_back(s[i]);
  vector<int> v, cnt(d, 0);
  for (int i = 0; i < n; i++) v.push_back(q[i]), cnt[p[i]]++;
  for (int i = 0; i < m; i++) v.push_back(s[i]);
  sort(v.begin(), v.end());
  v.erase(unique(v.begin(), v.end()), v.end());
  int ans = INF, mx_b = -INF;
  for (int i = 1; i < (int) v.size(); i++) mx_b = max(mx_b, v[i] - v[i - 1]);
  if ((int) v.size() >= 2) mx_b = max(mx_b, v[0] - v.back() + d);
  vector<int> smaller_1(d, -1), larger_1(d, -1);
  for (int i = 0; i < (int) v.size(); i++) {
    smaller_1[v[i]] = v[(i + 1) % (int) v.size()];
    larger_1[v[((i - 1) + (int) v.size()) % (int) v.size()]] = v[i];
  }
  for (int l = 0; l < d; l++) {
    int mx = mx_b, cnt_1 = 0, left = (int) v.size();
    vector<int> larger = larger_1, smaller = smaller_1;
    for (int r = l; r < l + d; r++) {
      int tmp_r = r; r %= d;
      cnt_1 += cnt[r];
      for (auto &x : type_2[r]) {
        mx = max(mx, (larger[x] - smaller[x] + d) % d);
        smaller[larger[x]] = smaller[x];
        larger[smaller[x]] = larger[x];
        if (--left <= 1) mx = d;
      }
      r = tmp_r;
      if (cnt_1 == n) ans = min(ans, (r - l + 1) * (d - mx + 1));
    }
    for (auto &x : by_r[l]) {
      if (type_1[x]) continue;
      type_2[last[x] % d].erase(x);
      last[x] = l + d;
      type_2[last[x] % d].insert(x);
    }
  }
  cout << ans << '\n';
  return 0;
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 6
• Subtask 3: 0 / 8
• Subtask 4: 0 / 16
• Subtask 5: 0 / 30
• Subtask 6: 0 / 25