Submission #831852

#	Time	Username	Problem	Language	Result	Execution time	Memory
831852		WLZ	Garden (JOI23_garden)	C++17	45 / 100	3054 ms	11508 KiB

garden

#include <bits/stdc++.h>
using namespace std;

const int INF = 0x3f3f3f3f;

int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  int n, m, d; cin >> n >> m >> d;
  vector<int> p(n), q(n), r(m), s(m);
  for (int i = 0; i < n; i++) cin >> p[i] >> q[i];
  for (int i = 0; i < m; i++) cin >> r[i] >> s[i];
  vector<bool> type_1(d, false);
  for (int i = 0; i < n; i++) type_1[q[i]] = true;
  vector<int> last(d, -1);
  for (int i = 0; i < m; i++) if (!type_1[s[i]]) last[s[i]] = max(last[s[i]], r[i]);
  vector< set<int> > type_2(d, set<int>());
  for (int i = 0; i < d; i++) if (last[i] != -1) type_2[last[i]].insert(i);
  vector< vector<int> > by_r(d);
  for (int i = 0; i < m; i++) by_r[r[i]].push_back(s[i]);
  set<int> all;
  vector<int> v, cnt(d, 0);
  for (int i = 0; i < n; i++) all.insert(q[i]), v.push_back(q[i]), cnt[p[i]]++;
  for (int i = 0; i < m; i++) all.insert(s[i]), v.push_back(s[i]);
  sort(v.begin(), v.end());
  int ans = INF, mx_b = -INF;
  for (int i = 1; i < (int) v.size(); i++) mx_b = max(mx_b, v[i] - v[i - 1]);
  if ((int) v.size() >= 2) mx_b = max(mx_b, v[0] - v.back() + d);
  for (int l = 0; l < d; l++) {
    int mx = mx_b, cnt_1 = 0;
    set<int> st = all;
    for (int r = l; r < l + d; r++) {
      int tmp_r = r; r %= d;
      cnt_1 += cnt[r];
      for (auto &x : type_2[r]) {
        auto it = st.find(x);
        if ((int) st.size() > 2) {
          set<int>::iterator prv, nxt = next(it);
          if (it == st.begin()) prv = prev(st.end());
          else prv = prev(it);
          if (nxt == st.end()) nxt = st.begin();
          mx = max(mx, (*nxt - *prv + d) % d);
        }
        st.erase(x);
        if ((int) st.size() <= 1) mx = d;
      }
      r = tmp_r;
      if (cnt_1 == n) ans = min(ans, (r - l + 1) * (d - mx + 1));
    }
    for (auto &x : by_r[l]) {
      if (type_1[x]) continue;
      type_2[last[x] % d].erase(x);
      last[x] = l + d;
      type_2[last[x] % d].insert(x);
    }
  }
  cout << ans << '\n';
  return 0;
}

• Subtask 1: 15 / 15
• Subtask 2: 6 / 6
• Subtask 3: 8 / 8
• Subtask 4: 16 / 16
• Subtask 5: 0 / 30
• Subtask 6: 0 / 25