Submission #831341

#	Time	Username	Problem	Language	Result	Execution time	Memory
831341		maomao90	Giraffes (JOI22_giraffes)	C++17	10 / 100	7023 ms	340 KiB

giraffes

// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h> 
using namespace std;

#define REP(i, s, e) for (int i = (s); i < (e); i++)
#define RREP(i, s, e) for (int i = (s); i >= (e); i--)
template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}

typedef unsigned long long ull;
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define SZ(_a) (int) _a.size()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

const int INF = 1000000005;
const ll LINF = 1000000000000000005ll;
const int MAXN = 200005;

int n;
int p[MAXN];
int a[MAXN];
int ans;

int main() {
#ifndef DEBUG
    ios::sync_with_stdio(0), cin.tie(0);
#endif
    cin >> n;
    REP (i, 0, n) {
        cin >> p[i];
    }
    ans = n;
    iota(a, a + n, 1);
    do {
        bool bad = 0;
        REP (i, 0, n) {
            ii mn = {INF, INF}, mx = {-INF, -INF};
            REP (j, i, n) {
                mnto(mn, {a[j], j});
                mxto(mx, {a[j], j});
                if (mn.SE != i && mn.SE != j && mx.SE != i && mx.SE != j) {
                    bad = 1;
                    break;
                }
            }
            if (bad) {
                break;
            }
        }
        if (bad) {
            continue;
        }
        int cost = 0;
        REP (i, 0, n) {
            cost += a[i] != p[i];
        }
        mnto(ans, cost);
    } while (next_permutation(a, a + n));
    cout << ans << '\n';
    return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 0 / 22
• Subtask 3: 0 / 27
• Subtask 4: 0 / 41