Submission #83078

#	Time	Username	Problem	Language	Result	Execution time	Memory
83078		luckyboy	Dostavljač (COCI18_dostavljac)	C++14	140 / 140	282 ms	2696 KiB

dostavljac

/**Lucky Boy**/
#include <bits/stdc++.h>
#define FOR(i, a, b) for (int i = (a); i <= (b); ++i)
#define FORD(i, a, b) for (int i = (a); i >= (b); --i)
#define pb push_back
#define mp make_pair
#define F first
#define S second
#define maxc 1000000007
#define maxn 505
#define maxm 500005
#define pii pair <int,int>
#define Task "Dosta"
template <typename T> inline void read(T &x){char c;bool nega=0;while((!isdigit(c=getchar()))&&(c!='-'));if(c=='-'){nega=1;c=getchar();}x=c-48;while(isdigit(c=getchar())) x=x*10+c-48;if(nega) x=-x;}
template <typename T> inline void writep(T x){if(x>9) writep(x/10);putchar(x%10+48);}
template <typename T> inline void write(T x){if(x<0){putchar('-');x=-x;}writep(x);putchar(' ');}
template <typename T> inline void writeln(T x){write(x);putchar('\n');}
using namespace std;
int n,t,val[maxn],dp[maxn][maxn][2],ans;
vector <int> a[maxn];
void Dfs(int u,int par)
{
    dp[u][0][0] = dp[u][0][1] = 0;
    dp[u][1][0] = dp[u][1][1] = val[u];
    for (int v : a[u])
        if (v != par)
        {
            Dfs(v,u);
            FORD(i,t,1)
                FOR(j,0,i)
                {
                    if (i - j - 1 >= 0)
                    {
                        dp[u][i][0] = max(dp[u][i][0],dp[u][j][1] + dp[v][i-j-1][0]);
                        //dp[u][i][0] = max(dp[u][i][0],dp[u][j][0] + dp[v][i-j-1][1]);
                    }
                    if (i - j - 2 >= 0)
                    {
                        dp[u][i][1] = max(dp[u][i][1],dp[u][j][1] + dp[v][i-j-2][1]);
                        dp[u][i][0] = max(dp[u][i][0],dp[u][j][0] + dp[v][i-j-2][1]);
                    }
                }
        }
}
int main()
{
    //ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    //freopen(Task".inp", "r",stdin);
    //freopen(Task".out", "w",stdout);
    read(n),read(t);
    FOR(i,1,n) FOR(j,0,t) dp[i][j][0] = dp[i][j][1] = -maxc;
    FOR(i,1,n) read(val[i]);
    FOR(i,1,n-1)
    {
        int x,y;
        read(x),read(y);
        a[x].pb(y);
        a[y].pb(x);
    }
    Dfs(1,0);
    int ans = 0;
    FOR(i,1,t) ans = max(ans,max(dp[1][i][0],dp[1][i][1]));
    write(ans);
    return 0;
}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 14 / 14
• Subtask 4: 14 / 14
• Subtask 5: 14 / 14
• Subtask 6: 14 / 14
• Subtask 7: 14 / 14
• Subtask 8: 14 / 14
• Subtask 9: 14 / 14
• Subtask 10: 14 / 14