Submission #830704

#	Time	Username	Problem	Language	Result	Execution time	Memory
830704		green_gold_dog	Sandcastle 2 (JOI22_ho_t5)	C++17	71 / 100	5079 ms	372892 KiB

Main

#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,sse,sse2,sse3,ssse3,sse4,abm,popcnt,mmx")
#include <bits/stdc++.h>

using namespace std;

typedef int ll;
typedef double db;
typedef long double ldb;
typedef complex<double> cd;

constexpr ll INF64 = 9'000'000'000'000'000'000, INF32 = 2'000'000'000, MOD = 1'000'000'007;
constexpr db PI = acos(-1);
constexpr bool IS_FILE = false, IS_TEST_CASES = false;

random_device rd;
mt19937 rnd32(rd());
mt19937_64 rnd64(rd());

template<typename T>
bool assign_max(T& a, T b) {
        if (b > a) {
                a = b;
                return true;
        }
        return false;
}

template<typename T>
bool assign_min(T& a, T b) {
        if (b < a) {
                a = b;
                return true;
        }
        return false;
}

template<typename T>
T square(T a) {
        return a * a;
}

template<>
struct std::hash<pair<ll, ll>> {
        ll operator() (pair<ll, ll> p) const {
                return ((__int128)p.first * MOD + p.second) % INF64;
        }
};

ll get(vector<vector<vector<vector<vector<vector<ll>>>>>>& dp2, vector<vector<vector<vector<vector<vector<ll>>>>>>& pref, ll x1, ll y1, ll x2, ll y2, ll xg) {
        ll bu = min(2, xg - x1), bd = min(2, x2 - xg);
        if (y2 - y1 > 4) {
                return pref[xg][y2 - 2][bu][2][bd][2] - pref[xg][y1 + 2][bu][2][bd][2] + dp2[xg][y1][bu][0][bd][2] + dp2[xg][y1 + 1][bu][1][bd][2] + dp2[xg][y2 - 1][bu][2][bd][0] + dp2[xg][y2 - 2][bu][2][bd][1];
        }
        if (y2 - y1 == 4) {
                return dp2[xg][y1][bu][0][bd][2] + dp2[xg][y1 + 1][bu][1][bd][2] + dp2[xg][y2 - 1][bu][2][bd][0] + dp2[xg][y2 - 2][bu][2][bd][1];
        }
        if (y2 - y1 == 3) {
                return dp2[xg][y1][bu][0][bd][2] + dp2[xg][y1 + 1][bu][1][bd][1] + dp2[xg][y2 - 1][bu][2][bd][0];
        }
        if (y2 - y1 == 2) {
                return dp2[xg][y1][bu][0][bd][1] + dp2[xg][y2 - 1][bu][1][bd][0];
        }
        if (y2 - y1 == 1) {
                return dp2[xg][y1][bu][0][bd][0];
        }
        return 0;
}

void solve() {
        ll n, m;
        cin >> n >> m;
        bool b = false;
        if (n < m) {
                swap(n, m);
                b = true;
        }
        vector<vector<ll>> arr(n, vector<ll>(m));
        if (!b) {
                for (ll i = 0; i < n; i++) {
                        for (ll j = 0; j < m; j++) {
                                cin >> arr[i][j];
                        }
                }
        } else {
                for (ll i = 0; i < m; i++) {
                        for (ll j = 0; j < n; j++) {
                                cin >> arr[j][i];
                        }
                }
        }
        vector<vector<vector<vector<vector<vector<ll>>>>>> dp1(n, vector(m, vector(2, vector(2, vector(2, vector<ll>(2, -1))))));
        vector<vector<vector<vector<vector<vector<ll>>>>>> dp2(n, vector(m, vector(3, vector(3, vector(3, vector<ll>(3, 0))))));
        vector<vector<vector<vector<vector<vector<ll>>>>>> pref(n, vector(m + 1, vector(3, vector(3, vector(3, vector<ll>(3, 0))))));
        vector<vector<vector<vector<vector<ll>>>>> so(n, vector(m, vector(m + 1, vector(3, vector<ll>(3, 0)))));
        vector<vector<vector<vector<vector<ll>>>>> sop(n, vector(m, vector(m + 1, vector(3, vector<ll>(3, 0)))));
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        ll mi = -1;
                        for (ll bu = 0; bu <= 1; bu++) {
                                if (bu && i == 0) {
                                        continue;
                                }
                                ll fir = mi;
                                if (bu && arr[i][j] > arr[i - 1][j]) {
                                        assign_max(mi, arr[i - 1][j]);
                                }
                                for (ll bl = 0; bl <= 1; bl++) {
                                        if (bl && j == 0) {
                                                continue;
                                        }
                                        ll fir = mi;
                                        if (bl && arr[i][j] > arr[i][j - 1]) {
                                                assign_max(mi, arr[i][j - 1]);
                                        }
                                        for (ll bd = 0; bd <= 1; bd++) {
                                                if (bd && i == n - 1) {
                                                        continue;
                                                }
                                                ll fir = mi;
                                                if (bd && arr[i][j] > arr[i + 1][j]) {
                                                        assign_max(mi, arr[i + 1][j]);
                                                }
                                                for (ll br = 0; br <= 1; br++) {
                                                        if (br && j == m - 1) {
                                                                continue;
                                                        }
                                                        ll fir = mi;
                                                        if (br && arr[i][j] > arr[i][j + 1]) {
                                                                assign_max(mi, arr[i][j + 1]);
                                                        }
                                                        dp1[i][j][bu][bl][bd][br] = mi;
                                                        mi = fir;
                                                }
                                                mi = fir;
                                        }
                                        mi = fir;
                                }
                                mi = fir;
                        }
                }
        }
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        for (ll bu = 0; bu <= 2; bu++) {
                                if (i - bu < 0) {
                                        continue;
                                }
                                for (ll bl = 0; bl <= 2; bl++) {
                                        if (j - bl < 0) {
                                                continue;
                                        }
                                        for (ll bd = 0; bd <= 2; bd++) {
                                                if (i + bd >= n) {
                                                        continue;
                                                }
                                                for (ll br = 0; br <= 2; br++) {
                                                        if (j + br >= m) {
                                                                continue;
                                                        }
                                                        if (bu) {
                                                                dp2[i][j][bu][bl][bd][br] += arr[i][j] == dp1[i - 1][j][bu - 1][min(bl, 1)][1][min(br, 1)];
                                                        }
                                                        if (bd) {
                                                                dp2[i][j][bu][bl][bd][br] += arr[i][j] == dp1[i + 1][j][1][min(bl, 1)][bd - 1][min(br, 1)];
                                                        }
                                                        if (bl) {
                                                                dp2[i][j][bu][bl][bd][br] += arr[i][j] == dp1[i][j - 1][min(bu, 1)][bl - 1][min(bd, 1)][1];
                                                        }
                                                        if (br) {
                                                                dp2[i][j][bu][bl][bd][br] += arr[i][j] == dp1[i][j + 1][min(bu, 1)][1][min(bd, 1)][br - 1];
                                                        }
                                                        dp2[i][j][bu][bl][bd][br] ^= 1;
                                                        pref[i][j + 1][bu][bl][bd][br] = pref[i][j][bu][bl][bd][br] + dp2[i][j][bu][bl][bd][br];
                                                }
                                        }
                                }
                        }
                }
        }
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        for (ll k = j + 1; k <= m; k++) {
                                for (ll bu = 0; bu <= 2; bu++) {
                                        if (i - bu < 0) {
                                                continue;
                                        }
                                        for (ll bd = 0; bd <= 2; bd++) {
                                                if (i + bd >= n) {
                                                        continue;
                                                }
                                                so[i][j][k][bu][bd] = get(dp2, pref, i - bu, j, i + bd, k, i);
                                        }
                                }
                        }
                }
        }
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        for (ll k = j + 1; k <= m; k++) {
                                for (ll bu = 0; bu <= 2; bu++) {
                                        if (i - bu < 0) {
                                                continue;
                                        }
                                        for (ll bd = 0; bd <= 2; bd++) {
                                                if (i + bd >= n) {
                                                        continue;
                                                }
                                                sop[i][j][k][bu][bd] = so[i][j][k][bu][bd] + (bd > 0 ? so[i + 1][j][k][min(2, bu + 1)][bd - 1] : 0);
                                        }
                                }
                        }
                }
        }
        ll ans = 0;
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        for (ll k = j + 1; k <= m; k++) {
                                ll na = 0;
                                for (ll aj = 0; aj + i < n; aj++) {
                                        if (aj >= 2) {
                                                na += so[i + aj - 2][j][k][min(2, aj - 2)][2];
                                                if (na > 1) {
                                                        break;
                                                }
                                        }
                                        ll naj = max(0, aj - 1);
                                        if (na + sop[i + naj][j][k][min(2, naj)][aj - naj] == 1) {
                                                ans++;
                                        }
                                }
                        }
                }
        }
        cout << ans << '\n';
}

int main() {
        if (IS_FILE) {
                freopen("", "r", stdin);
                freopen("", "w", stdout);
        }
        ios_base::sync_with_stdio(false);
        cin.tie(0);
        cout.tie(0);
        ll t = 1;
        if (IS_TEST_CASES) {
                cin >> t;
        }
        for (ll i = 0; i < t; i++) {
                solve();
        }
}

Compilation message (stderr)

Main.cpp:12:22: warning: overflow in conversion from 'long int' to 'll' {aka 'int'} changes value from '9000000000000000000' to '-494665728' [-Woverflow]
   12 | constexpr ll INF64 = 9'000'000'000'000'000'000, INF32 = 2'000'000'000, MOD = 1'000'000'007;
      |                      ^~~~~~~~~~~~~~~~~~~~~~~~~
Main.cpp: In function 'int main()':
Main.cpp:240:24: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  240 |                 freopen("", "r", stdin);
      |                 ~~~~~~~^~~~~~~~~~~~~~~~
Main.cpp:241:24: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  241 |                 freopen("", "w", stdout);
      |                 ~~~~~~~^~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 9
• Subtask 2: 10 / 10
• Subtask 3: 5 / 5
• Subtask 4: 56 / 56
• Subtask 5: 0 / 20