Submission #827872

#	Time	Username	Problem	Language	Result	Execution time	Memory
827872		BT21tata	Global Warming (CEOI18_glo)	C++17	45 / 100	38 ms	3804 KiB

glo

#include<bits/stdc++.h>
// #include <ext/pb_ds/assoc_container.hpp>
// using namespace __gnu_pbds;
// #pragma GCC target ("avx,avx2,fma")
// #pragma GCC optimize("Ofast")
// #pragma GCC optimize("unroll-loops")
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
#define SPEED ios_base::sync_with_stdio(false); cin.tie(0), cout.tie(0)
#define rall(v) (v).rbegin(),(v).rend()
#define all(v) (v).begin(),(v).end()
#define setp fixed<<setprecision
#define OK cerr<<"OK"<<endl<<flush
#define pii pair<int, int>
#define pll pair<ll, ll>
#define pb push_back
#define F first
#define S second
#define y0 jahdakdh
#define y1 jahsadakdakdh
#define endl '\n'
const ll MOD=1e9+7;
const ll mod=(1ll<<31)-1;
const ld eps=1e-8;
const ll MAXLONG=9223372036854775807;
const ll MINLONG=-9223372036854775807;
using namespace std;
mt19937 rng(std::chrono::system_clock::now().time_since_epoch().count());
const int N=2e5+5;
 
int n, x, a[N], ans, fs[N];
 
vector<int> LIS()
{
    vector<int>v{a[0]}, ret{1};
    for(int i=1; i<n; i++)
    {
        if(v.back()<a[i])
        {
            v.pb(a[i]);
            ret.pb(v.size());
        }
        else
        {
            int pos=lower_bound(all(v), a[i])-v.begin();
            v[pos]=a[i];
            ret.pb(pos+1);
        }
    }
    return ret;
}
 
int main()
{
    SPEED;
    cin>>n>>x;
    for(int i=0; i<n; i++)
        cin>>a[i];
    vector<int>l = LIS();
    
    reverse(a, a+n);
    for(int i=0; i<n; i++)
        a[i]=-a[i];
    vector<int>r = LIS();
    reverse(all(r));
 
    reverse(a, a+n);
    for(int i=0; i<n; i++)
        a[i]=-a[i];
    a[n]=MOD;
 
    for(int i=n-1; i>=0; i--)
    {
        fs[i]=i+1;
        while(a[fs[i]]+x<=a[i]) fs[i]=fs[fs[i]];
        //cout<<i<<' '<<l[i]<<' '<<r[i]<<' '<<fs[i]<<endl;
        ans=max(ans, l[i]+r[fs[i]]);
    }
    cout<<ans<<endl;
    return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 10 / 10
• Subtask 3: 0 / 13
• Subtask 4: 10 / 10
• Subtask 5: 20 / 20
• Subtask 6: 0 / 17
• Subtask 7: 0 / 25