Submission #827434

#TimeUsernameProblemLanguageResultExecution timeMemory
827434MadokaMagicaFanLottery (CEOI18_lot)C++14
80 / 100
461 ms9292 KiB
#include "bits/stdc++.h" using namespace std; using ll = long long; #define pb push_back #define sz(v) ((int)v.size()) const ll inf = 1e16; const int N = 10000; int n, l, q; vector<int> nm, v, ks; vector<array<int,100>> ans; int j[N], lst[N], e[N], prec[N+1]; int bs(int x) { int l, r, m; l = 0; r = sz(nm); while (l < r) { m = (l+r)/2; if (nm[m] <= x) l = m+1; else r = m; } return l - 1; } int bs2(int x) { int l, r, m; l = 0; r = sz(ks); while (l < r) { m = (l+r)/2; if (ks[m] <= x) l = m+1; else r = m; } return l; } void _add(int x) { if (j[x] == 0) return; int d = x; do { d -= j[d]; ++e[x-d]; } while (j[d]); } void _rem(int x) { if (j[x] == 0) return; int d = x; do { d -= j[d]; --e[x-d]; } while (j[d]); } void solve() { for (int i = 0; i < n; ++i) { j[i] = 0; lst[i] = -1; e[i] = 0; } for (int i = 0; i < n; ++i) { if (lst[v[i]] != -1) j[i] = i - lst[v[i]]; lst[v[i]] = i; } for (int i = 0; i < l; ++i) _add(i); for (int i = 1; i + l - 1 < n; ++i) { _add(i+l-1); _rem(i-1); for (int j = 1; j <= i; ++j) { if (prec[e[j]]) ans[i][prec[e[j]]-1]++; } } } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> n >> l; v.assign(n, 0); ans.resize(n-l+1); for (int i = 0; i < n; ++i) cin >> v[i]; for (int i = 0; i < n - l + 1; ++i) for (int j = 0; j < 100; ++j) ans[i][j] = 0; nm = v; sort(nm.begin(), nm.end()); nm.erase(unique(nm.begin(), nm.end()), nm.end()); for (int i = 0; i < n; ++i) v[i] = bs(v[i]); cin >> q; vector<int> qq(q); for (int i = 0; i < q; ++i) cin>>qq[i]; for (int i = 0; i < q; ++i) ks.pb(l - qq[i]); sort(ks.begin(), ks.end()); ks.erase(unique(ks.begin(), ks.end()), ks.end()); for (int i = 0; i <= n; ++i) prec[i] = bs2(i); solve(); reverse(v.begin(), v.end()); reverse(ans.begin(), ans.end()); solve(); reverse(ans.begin(), ans.end()); for (int i = sz(ks)-1; i >= 0; --i) for (int j = 0; j < n - l + 1; ++j) ans[j][i] += ans[j][i+1]; for (int i = 0; i < q; ++i) { for (int j = 0; j < n - l + 1; ++j) cout << ans[j][bs2(l-qq[i])-1] << (j == n-l ? '\n' : ' '); } }
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