Submission #827420

#	Time	Username	Problem	Language	Result	Execution time	Memory
827420		MadokaMagicaFan	Lottery (CEOI18_lot)	C++14	80 / 100	2691 ms	9368 KiB

lot

#include "bits/stdc++.h"
using namespace std;
using ll = long long;
#define pb push_back
#define sz(v) ((int)v.size())

const ll inf = 1e16;
const int N = 10000;
int n, l, q;

vector<int> nm, v, ks;
vector<array<int,100>> ans;
int j[N], lst[N], e[N];
int bs(int x) {
	int l, r, m;
	l = 0;
	r = sz(nm);
	while (l < r) {
		m = (l+r)/2;
		if (nm[m] <= x)
			l = m+1;
		else
			r = m;
	}
	return l - 1;
}
int bs2(int x) {
	int l, r, m;
	l = 0;
	r = sz(ks);
	while (l < r) {
		m = (l+r)/2;
		if (ks[m] <= x)
			l = m+1;
		else
			r = m;
	}
	return l;
}

void _add(int x) {
	if (j[x] == 0) return;
	int d = x;
	do {
		d -= j[d];
		++e[x-d];
	} while (j[d]);
}

void _rem(int x) {
	if (j[x] == 0) return;
	int d = x;
	do {
		d -= j[d];
		--e[x-d];
	} while (j[d]);
}

void solve() {
	int u;
	for (int i = 0; i < n; ++i) {
		j[i] = 0; lst[i] = -1; e[i] = 0;
	}

	for (int i = 0; i < n; ++i) {
		if (lst[v[i]] != -1)
			j[i] = i - lst[v[i]];
		lst[v[i]] = i;
	}
	
	for (int i = 0; i < l; ++i)
		_add(i);

	for (int i = 1; i + l - 1 < n; ++i) {
		_add(i+l-1); _rem(i-1);
		for (int j = 1; j <= i; ++j) {
			u = bs2(e[j]);
			if (u) ans[i][u-1]++;
		}
	}
}



int main() {
	ios_base::sync_with_stdio(0); cin.tie(0);
	cin >> n >> l;
	v.assign(n, 0);
	ans.resize(n-l+1);
	for (int i = 0; i < n; ++i) cin >> v[i];
	for (int i = 0; i < n - l + 1; ++i)
		for (int j = 0; j < 100; ++j) ans[i][j] = 0;
	nm = v; sort(nm.begin(), nm.end()); nm.erase(unique(nm.begin(), nm.end()), nm.end());
	for (int i = 0; i < n; ++i) v[i] = bs(v[i]);
	cin >> q;
	vector<int> qq(q);
	for (int i = 0; i < q; ++i)
		cin>>qq[i];
	for (int i = 0; i < q; ++i)
		ks.pb(l - qq[i]);
	sort(ks.begin(), ks.end()); ks.erase(unique(ks.begin(), ks.end()), ks.end());

	solve();
	reverse(v.begin(), v.end());
	reverse(ans.begin(), ans.end());
	solve();
	reverse(ans.begin(), ans.end());
	for (int i = sz(ks)-1; i >= 0; --i)
		for (int j = 0; j < n - l + 1; ++j)
			ans[j][i] += ans[j][i+1];

	for (int i = 0; i < q; ++i) {
		for (int j = 0; j < n - l + 1; ++j)
			cout << ans[j][bs2(l-qq[i])-1] << (j == n-l ? '\n' : ' ');
	}
}

• Subtask 1: 25 / 25
• Subtask 2: 20 / 20
• Subtask 3: 20 / 20
• Subtask 4: 15 / 15
• Subtask 5: 0 / 20