Submission #821886

#	Time	Username	Problem	Language	Result	Execution time	Memory
821886		NK_	Cloud Computing (CEOI18_clo)	C++17	100 / 100	255 ms	1236 KiB

clo

// Success consists of going from failure to failure without loss of enthusiasm
#pragma GCC optimize("O3,unroll-loops")
#include <bits/stdc++.h>
 
using namespace std;
 
#define nl '\n'
#define pb push_back
 
using ll = long long;
 
template<class T> using V = vector<T>;
using vi = V<int>;
using vl = V<ll>;
 
const int nax = int(1e5) + 5;
 
ll dp[nax];
V<array<int, 4>> A;
int main() {
	cin.tie(0)->sync_with_stdio(0);
	
	int N; cin >> N;
 
	for(int i = 0; i < N; i++) {
		int c, f, v; cin >> c >> f >> v;
		A.pb(array<int, 4>{f, 1, c, v});
	}
 
	int M; cin >> M;
	for(int i = 0; i < M; i++) {
		int c, f, v; cin >> c >> f >> v;
		A.pb(array<int, 4>{f, -1, c, v});
	}
 
	sort(begin(A), end(A), [&](const array<int, 4> &a, const array<int, 4> &b) {
		if (a[0] == b[0]) return a[1] < b[1];
		else return a[0] < b[0];
	});
 
	memset(dp, -1, sizeof dp); dp[0] = 0;
	int MX = 0;
	for(int i = 0; i < N + M; i++) {
		int c = A[i][2], v = A[i][3], y;
		if (A[i][1] == -1) {
			for(int x = MX; x >= 0; x--) if (dp[x] != -1) {
				y = x + c;
				if (y < nax) dp[y] = max(dp[x] + v, dp[y]);
			}
			MX += c;
		} else {
			for(int x = 0; x <= MX; x++) if (dp[x] != -1) {
				if (x < c) y = 0;
				else y = x - c;
				dp[y] = max(dp[x] - v, dp[y]);
			}
		}
	}
 
	cout << dp[0] << nl;
 
    return 0;
}

• Subtask 1: 18 / 18
• Subtask 2: 18 / 18
• Subtask 3: 18 / 18
• Subtask 4: 18 / 18
• Subtask 5: 18 / 18
• Subtask 6: 10 / 10