이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <algorithm>
#include <set>
using namespace std;
const int N = 107;
typedef long long ll;
const ll MOD = 1e9+7;
int A[N];
ll dp[N][2]; // 0 - prev was not split, 1 - prev was split
ll X(int n){
if (n<0){
return 0;
}
return (n+2)/2;
}
void normalize(int *A,int &n){
multiset<int> S;
for(int i = 1;i<=n;i+=1){
S.insert(A[i]);
}
int ptr = 0;
while(!S.empty()){
int v = *S.begin();
S.erase(S.begin());
if (v==0 && S.count(v)!=0){
S.erase(S.lower_bound(0));
S.insert(1);
}
else if (S.count(v+1)!=0){
S.erase(S.lower_bound(v+1));
S.insert(v+2);
}
else{
A[++ptr] = v;
}
}
n = ptr;
}
int M[N];
bool compare(int *A,int *B,int sz){
for(int i = 1;i<=sz;i+=1){
if (A[i]!=B[i]){
return 0;
}
}
return 1;
}
ll calc(int &n){
normalize(A,n);
int ret = 0;
for(int mask = 0;mask<(1<<(A[n]+1));mask+=1){
int ptr = 0;
for(int bit = 0;bit<A[n]+1;bit+=1){
if (mask&(1<<bit)){
M[++ptr] = bit;
}
}
normalize(M,ptr);
if (ptr==n && compare(A,M,ptr)){
ret += 1;
}
}
return ret;
}
ll solve(int &n){
normalize(A,n);
dp[0][0] = 1;
for(int i = 1;i<=n;i+=1){
dp[i][0] = (A[i-1]!=A[i]?dp[i-1][0]:0)+dp[i-1][1];
dp[i][1] = dp[i-1][0]*X(A[i]-2-A[i-1])+dp[i-1][1]*X(A[i]-2-(A[i-1]-1));
dp[i][0] %= MOD;
dp[i][1] %= MOD;
}
return (dp[n][0]+dp[n][1])%MOD;
}
int main(){
int n;
cin>>n;
int sz = 0;
for(int i = 1;i<=n;i+=1){
cin>>A[++sz];
A[sz] -= 1;
cout<<calc(sz)<<'\n';
}
}
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