Submission #810818

#TimeUsernameProblemLanguageResultExecution timeMemory
810818MyCodeA Difficult(y) Choice (BOI21_books)C++17
100 / 100
213 ms860 KiB
#include <bits/stdc++.h> #include "books.h" using namespace std; void solve(int n, int k, long long A, int S) { if (S == n) { long long a[n + 1]; for (int i = 1; i <= n; i++) a[i] = skim(i); long long pref[n + 1]; pref[0] = 0; for (int i = 1; i <= n; i++) pref[i] = a[i] + pref[i - 1]; function<long long(int, int)> sum = [&](int l, int r) { return pref[r] - pref[l - 1]; }; for (int i = 1; i <= n; i++) { if (sum(i, i + k - 1) >= A && sum(i, i + k - 1) <= 2 * A) { vector<int> ans; for (int j = i; j < i + k; j++) ans.emplace_back(j); answer(ans); return; } }; long long s[n + 1]; for (int i = 1; i + k - 2 <= n; i++) s[i] = sum(i, i + k - 2); for (int i = k; i <= n; i++) { int l = 1, r = i - k + 1; while (r - l > 1) { int m = (l + r) >> 1; if (s[m] + a[i] >= A) r = m; else l = m; } int ind = -1; if (s[l] + a[i] >= A)ind = l; else if (s[r] + a[i] >= A)ind = r; if (ind != -1 && s[ind] + a[i] <= 2 * A) { vector<int> ans; for (int j = ind; j < ind + k - 1; j++) ans.emplace_back(j); ans.emplace_back(i); answer(ans); return; } } impossible(); return; } long long sum = 0; vector<pair<int, long long>> ans; map<int, long long> mp; function<long long(int)> skimm = [&](int i) { if (mp.find(i) != mp.end()) return mp[i]; long long s = skim(i); mp[i] = s; return s; }; for (int i = 1; i <= k; i++) { long long t = skimm(i); sum += t; ans.emplace_back(i, t); } for (int j = k; j >= 1; j--) { if (sum >= A)break; int l = ans[j - 1].first, r = (j < k ? ans[j].first - 1 : n); long long val = ans[j - 1].second; long long X = skimm(r); if (sum + X <= 2 * A) { ans[j - 1].first = r; sum -= ans[j - 1].second; ans[j - 1].second = X; sum += ans[j - 1].second; continue; } while (r - l > 1) { int m = (l + r) / 2; if (sum - val + skimm(m) >= A) r = m; else l = m; } long long s1 = skimm(l), s2 = skimm(r); if (sum - val + s2 > 2 * A || sum - val + s1 >= A) ans[j - 1].first = l, ans[j - 1].second = s1, sum = sum - val + s1; else ans[j - 1].first = r, ans[j - 1].second = s2, sum = sum - val + s2; } if (sum > 2 * A || sum < A) impossible(); else { vector<int> res; for (int i = 0; i < k; i++) res.emplace_back(ans[i].first); answer(res); } }
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