Submission #810245

#	Time	Username	Problem	Language	Result	Execution time	Memory
810245		acatmeowmeow	Sjeckanje (COCI21_sjeckanje)	C++11	0 / 110	15 ms	37844 KiB

Main

#include <bits/stdc++.h>

using namespace std;

#define int long long 

const int N = 2e5;
int n, q, arr[N + 5];

struct info {
	int mx[2][2] = {}, first, last;
	info operator+(info x) {
		info ans;
		ans.first = first, ans.last = x.last;
		for (int i = 0; i < 2; i++) {
			for (int j = 0; j < 2; j++) {
				for (int k = 0; k < 2; k++) {
					for (int l = 0; l < 2; l++) {
						ans.mx[i][l] = max(ans.mx[i][l], mx[i][j] + x.mx[k][l] + (j == 1 && k == 1 ? abs(last - x.first) : 0));
					}
				}
			}
		}
		return ans;
	}
};

info tree[4*N + 5];
int lazy[4*N + 5];

void init(int v, int tl, int tr) {
	if (tl == tr) tree[v].first = tree[v].last = arr[tl];
	else {
		int tm = (tl + tr)/2;
		init(v*2, tl, tm);
		init(v*2 + 1, tm + 1, tr);
		tree[v] = tree[v*2] + tree[v*2 + 1];
	}
}

void extend(int v, int tl, int tr) {
	tree[v*2].first += lazy[v], tree[v*2].last += lazy[v];
	tree[v*2 + 1].first += lazy[v], tree[v*2 + 1].last += lazy[v];
	lazy[v*2] += lazy[v], lazy[v*2 + 1] += lazy[v];
	lazy[v] = 0;
}

void update(int v, int tl, int tr, int l, int r, int x) {
	if (l > r) return;
	else if (tl == l && tr == r) tree[v].first += x, tree[v].last += x, lazy[v] += x;
	else {
		extend(v, tl, tr);
		int tm = (tl + tr)/2;
		update(v*2, tl, tm, l, min(tm, r), x);
		update(v*2 + 1, tm + 1, tr, max(l, tm + 1), r, x);
		tree[v] = tree[v*2] + tree[v*2 + 1];
	}
}

info query(int v, int tl, int tr, int l, int r) {
	if (tl == l && tr == r) return tree[v];
	else {
		extend(v, tl, tr);
		int tm = (tl + tr)/2;
		bool lef = l <= min(tm, r), rig = max(l, tm + 1) <= r;
		if (lef && rig) return query(v*2, tl, tm, l, min(tm, r)) + query(v*2 + 1, tm + 1, tr, max(l, tm + 1), r);
		else if (lef) return query(v*2, tl, tm, l, min(tm, r));
		else return query(v*2 + 1, tm + 1, tr, max(l, tm + 1), r);
	}
}

signed main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	cin >> n >> q;
	for (int i = 1; i <= n; i++) cin >> arr[i];
	init(1, 1, n);
	while (q--) {
		int l, r, x;
		cin >> l >> r >> x;
		update(1, 1, n, l, r, x);
		cout << max({tree[1].mx[0][0], tree[1].mx[0][1], tree[1].mx[1][0], tree[1].mx[1][1]}) << '\n';
	}
	return 0;
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 40
• Subtask 3: 0 / 55