이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#ifndef SorahISA
#define SorahISA
#include SorahISA __FILE__ SorahISA
void solve() {
int N, K; cin >> N >> K;
vector<int> A(N+K);
for (int &x : A) cin >> x;
vector<int> chosen(N+K);
auto chk = [&](int sum) -> int {
fill(ALL(chosen), 0);
int cnt = 0;
for (int i = 0, j = N+K-1; i < j and cnt < N/2; ++i) {
while (i < j and A[i] + A[j] > sum) --j;
if (i < j and A[i] + A[j] == sum) ++cnt, chosen[i] = chosen[j] = 1, --j;
}
return cnt;
};
for (int fr = 0; fr <= K; ++fr) {
for (int bk = 0; fr+bk <= K; ++bk) {
if (chk(A[fr] + A[N+K-1-bk]) == N/2) {
for (int i = 0; i < N+K; ++i) {
if (chosen[i]) cout << A[i] << " ";
}
cout << "\n";
return;
}
}
}
}
int32_t main() {
fastIO();
int t = 1; // cin >> t;
for (int _ = 1; _ <= t; ++_) {
solve();
}
return 0;
}
#else
#ifdef local
#define _GLIBCXX_DEBUG 1
#endif
#pragma GCC optimize("Ofast", "unroll-loops")
#include <bits/stdc++.h>
using namespace std;
#define int int64_t
// #define double __float80
using pii = pair<int, int>;
template <typename T> using Prior = std::priority_queue<T>;
template <typename T> using prior = std::priority_queue<T, vector<T>, greater<T>>;
// #define X first
// #define Y second
#define eb emplace_back
#define ef emplace_front
#define ee emplace
#define pb pop_back
#define pf pop_front
#define ALL(x) begin(x), end(x)
#define RALL(x) rbegin(x), rend(x)
#define SZ(x) ((int)(x).size())
#ifdef local
#define fastIO() void()
#define debug(...) \
fprintf(stderr, "%sAt [%s], line %d: (%s) = ", "\u001b[33m", __FUNCTION__, __LINE__, #__VA_ARGS__), \
_do(__VA_ARGS__), fprintf(stderr, "%s", "\u001b[0m")
template <typename T> void _do(T &&_t) {cerr << _t << "\n";}
template <typename T, typename ...U> void _do(T &&_t, U &&..._u) {cerr << _t << ", ", _do(_u...);}
#else
#define fastIO() ios_base::sync_with_stdio(0), cin.tie(0)
#define debug(...) void()
#endif
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
template <typename T, typename U> bool chmin(T &lhs, U rhs) {return lhs > rhs ? lhs = rhs, 1 : 0;}
template <typename T, typename U> bool chmax(T &lhs, U rhs) {return lhs < rhs ? lhs = rhs, 1 : 0;}
#endif
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