#include <bits/stdc++.h>
//#pragma GCC optimize("O3")
//#pragma GCC optimize("unroll-loops")
using namespace std;
#define int long long
#define vi vector<int>
#define vl vector<long long>
#define vii vector<pair<int,int>>
#define vll vector<pair<long long,long long>>
#define pb push_back
#define ll long long
#define ld long double
#define nl '\n'
#define boost ios::sync_with_stdio(false)
#define mp make_pair
#define se second
#define fi first
#define fore(i, y) for(int i = 0; i < y; i++)
#define forr(i,x,y) for(int i = x;i<=y;i++)
#define forn(i,y,x) for(int i = y; i >= x; i--)
#define all(v) v.begin(),v.end()
#define sz(v) v.size()
#define clr(v,k) memset(v,k,sizeof(v))
#define rall(v) v.rbegin() , v.rend()
#define pii pair<int,int>
#define pll pair<ll , ll>
const ll MOD = 1e9 + 7;
const int INF = 1e18 + 1;
const int inf = 1e9 + 1;
ll gcd(ll a , ll b) {return b ? gcd(b , a % b) : a ;} // greatest common divisor (gcd)
ll lcm(ll a , ll b) {return a * (b / gcd(a , b));} // least common multiple (lcm)
// HERE IS THE SOLUTION
const int N = 100000;
vii adj[N];
int n , m , s , t , u , v;
void restore()
{
vi dist(n , INF);
priority_queue<pii> pq;
pq.push({0 , s});
dist[s] = 0;
vector<bool> vis(n , 0);
vi par(n , -1);
while(!pq.empty())
{
int cur = pq.top().se;
pq.pop();
if(vis[cur])
continue;
vis[cur] = 1;
for(auto [x , c] : adj[cur])
{
if(dist[x] > dist[cur] + c){
dist[x] = dist[cur] + c;
pq.push({-dist[x] , x});
par[x] = cur;
}
}
}
int last = t;
while(par[last] != -1)
{
int prev= par[last];
for(auto &[x , c] : adj[last])
{
if(x == prev)
{
c = 0;
}
}
for(auto &[x , c] : adj[prev])
{
if(x == last)
{
c = 0;
}
}
last = prev;
}
}
int dijkstra()
{
vi dist(n , INF);
priority_queue<pii> pq;
pq.push({0 , u});
dist[u] = 0;
vector<bool> vis(n , 0);
while(!pq.empty())
{
int cur = pq.top().se;
pq.pop();
if(vis[cur])
continue;
vis[cur] = 1;
for(auto [x , c] : adj[cur])
{
if(dist[x] > dist[cur] + c){
dist[x] = dist[cur] + c;
pq.push({-dist[x] , x});
}
}
}
return dist[v];
}
signed main()
{
cin>>n>>m>>s>>t>>u>>v;
u-- , v-- , t-- , s--;
fore(i , m)
{
int a , b,c;
cin>>a>>b>>c;
a-- , b--;
adj[a].pb({b , c});
adj[b].pb({a , c});
}
restore();
cout<<dijkstra()<<nl;
}
