Submission #805724

#TimeUsernameProblemLanguageResultExecution timeMemory
805724YesPyCheap flights (LMIO18_pigus_skrydziai)C++17
0 / 100
500 ms194748 KiB
#include <bits/stdc++.h> #define ff first #define ss second #define tcT template<class T #define fastio ios::sync_with_stdio(false);cin.tie(nullptr); #define ln '\n' #define nwln cout<<ln; using namespace std; tcT> using vr = vector<T>; using pi = pair<int, int>; using vi = vr<int>; using vpi = vr<pi>; using ll = long long; using oo = bool; #define maxs(i, j) (i = max(i, j)) #define fri(i,a,b) for(int i=(a); i<(b); ++i) #define each(x, a) for(auto& x: a) #define sz(x) int((x).size()) #define phb push_back #define eb emplace_back const int MX = (int) 3e5+3; ll N, M, ans; oo used[MX]; set<int> orz[MX]; vpi adj[MX]; inline void dfs(int u) { used[u] = true; ll res = 0, xam = 0, U, idx = 0; map<int, int> cur; each(x, adj[u]) { cur[x.ff] = idx++; res += x.ss; if(xam < x.ss) U = x.ff, xam = x.ss; } maxs(ans, res); // idk if this "if" is necessary if(!used[U]) { each(x, adj[U]) { if(!orz[u].count(x.ff)) continue; maxs(ans, xam + x.ss + adj[u][cur[x.ff]].ss); } } each(x, adj[u]) { if(!used[x.ff]) dfs(x.ff); } } int main() { fastio cin>>N>>M; while(M--) { int u, v, w; cin>>u>>v>>w; adj[u].eb(v, w); adj[v].eb(u, w); orz[u].insert(v); orz[v].insert(u); } fri(i,1,N+1) { if(used[i]) continue; dfs(i); } cout<<ans<<ln; return 0; } /* Wow, beautiful trick Two possible types: star or triangle Stars are easy, bottleneck are the triangles What I do is, if I'm on node v then between all its edges I choose the greatest one and try to match the rest... it can be proved it's correct Suppose the answer is not correct and let the max-weight triangle be p, q -> a q, r -> b r, p -> c Then, we're assuming there exists p, P -> greater than c, a but less than b q, Q -> greater than a, b but less than c r, R -> greater than b, c but less than a Contradiction! We're done :D */

Compilation message (stderr)

pigus_skrydziai.cpp: In function 'void dfs(int)':
pigus_skrydziai.cpp:35:23: warning: 'U' may be used uninitialized in this function [-Wmaybe-uninitialized]
   35 |  ll res = 0, xam = 0, U, idx = 0;
      |                       ^
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