This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "garden.h"
#include "gardenlib.h"
#include <bits/stdc++.h>
using namespace std;
const int MX = 150000;
int g[2 * MX];
int cycle[2 * MX];
char vis[2 * MX];
int turns[2 * MX][2];
void dfs(int cur, int z) {
if (cycle[cur] != -1) {
turns[cur][z] = cycle[cur];
return;
}
vis[cur] = 1;
if (!vis[g[cur]])
dfs(g[cur], z);
turns[cur][z] = turns[g[cur]][z] + 1;
}
void count_routes(int N, int M, int P, int R[][2], int Q, int G[]) {
int fs[N], sc[N];
for (int i = 0; i < N; i++)
fs[i] = -1;
for (int i = M - 1; i >= 0; i--) {
sc[R[i][1]] = fs[R[i][1]];
fs[R[i][1]] = R[i][0];
sc[R[i][0]] = fs[R[i][0]];
fs[R[i][0]] = R[i][1];
}
for (int i = 0; i < 2 * N; i++)
if (i >= N) {
if (sc[i - N] == -1)
g[i] = g[i - N];
else if (fs[sc[i - N]] == i - N)
g[i] = sc[i - N] + N;
else
g[i] = sc[i - N];
} else {
if (fs[fs[i]] == i)
g[i] = fs[i] + N;
else
g[i] = fs[i];
}
int cycleSize[2];
for (int z = 0; z < 2; z++) {
for (int i = 0; i < 2 * N; i++)
cycle[i] = -1;
memset(vis, 0, sizeof vis);
for (int i = 0; i < 2 * N; i++)
turns[i][z] = 2000000000;
cycleSize[z] = 0;
int cur = P + N * z;
while (!vis[cur]) {
vis[cur] = 1;
cycle[cur] = cycleSize[z]++;
cur = g[cur];
}
for (int i = 0; i < 2 * N; i++)
if (cycle[i] != -1)
cycle[i] = (cycleSize[z] - cycle[i]) % cycleSize[z];
if (cur != P + N * z) { //P is not in cycle
for (int i = 0; i < 2 * N; i++)
cycle[i] = -1;
cycle[P + N * z] = 0;
cycleSize[z] = 1;
}
memset(vis, 0, sizeof vis);
for (int i = 0; i < 2 * N; i++)
if (!vis[i])
dfs(i, z);
}
//for (int i = 0; i < 2 * N; i++)
//cout << i << ": " << turns[i][0] << " " << turns[i][1] << " " << g[i] << " " << fs[i] << " " << sc[i] << endl;
for (int i = 0; i < Q; i++) {
int ans = 0;
for (int j = 0; j < N; j++)
ans += ((turns[j][0] == G[i] ||
(cycleSize[0] > 1 && G[i] >= turns[j][0] && (G[i] - turns[j][0]) % cycleSize[0] == 0)) ||
(turns[j][1] == G[i] ||
(cycleSize[1] > 1 && G[i] >= turns[j][1] && (G[i] - turns[j][1]) % cycleSize[1] == 0)));
answer(ans);
}
}
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