Submission #798538

#	Time	Username	Problem	Language	Result	Execution time	Memory
798538		cryan	Bank (IZhO14_bank)	C++14	0 / 100	4 ms	596 KiB

bank

// oh, these hills, they burn so bright / oh, these hills, they bring me life
#include "bits/stdc++.h"
using namespace std;

using ll = long long;
#define all(x) begin(x), end(x)
#define rall(x) x.rbegin(), x.rend()
#define sz(x) (int)(x.size())
#define inf 1000000010
#define linf 0x3f3f3f3f3f3f3f3f
#define mp make_pair
#define f first
#define s second
#define pi pair<int, int>
#ifdef __INTELLISENSE__
#include "/mnt/c/yukon/pp.hpp"
#endif
#ifndef LOCAL
#define endl "\n"
#else
#include "/mnt/c/yukon/pp.hpp"
#endif

int main() {
	int n, m;
	cin >> n >> m;

	vector<int> a(n + 1);
	for (int i = 1; i <= n; i++) {
		cin >> a[i];
	}

	vector<int> b(m);
	for (int i = 0; i < m; i++) {
		cin >> b[i];
	}

	vector<vector<vector<int>>> combos(n + 1);

	for (int i = 1; i <= n; i++) {
		vector<vector<vector<int>>> pp(a[i] + 1);
		pp[0].push_back(vector<int>());

		for (int bank = 0; bank < m; bank++) {
			for (int val = 1; val <= a[i]; val++) {
				if (val - b[bank] >= 0) {
					int bruhmoment = sz(pp[val]);
					pp[val].insert(pp[val].end(), pp[val - b[bank]].begin(), pp[val - b[bank]].end());
					for (int l = bruhmoment; l < sz(pp[val]); l++) {
						pp[val][l].push_back(b[bank]);
					}
				}
			}
		}

		combos[i] = pp[a[i]];
	}

	vector<vector<bool>> dp(n + 1, vector<bool>(1 << m, false));

	dp[0][0] = 1;

	for (int i = 1; i <= n; i++) {
		for (auto &k : combos[i]) {
			for (int mask = 0; mask < (1 << m); mask++) {
				bool good = 1;
				int before = mask;
				for (int &l : k) {
					if (mask & (1 << l)) {
						good = 0;
						break;
					}
					before ^= (1 << l);
				}
				if (!good)
					continue;

				dp[i][mask] = dp[i - 1][before];
				if (i == n && dp[i][mask]) {
					cout << "YES" << endl;
					return 0;
				}
			}
		}
	}
	cout << "NO" << endl;
}

// don't get stuck on one approach
// question bounds
// flesh out your approach before implementing o.o
// math it out
// ok well X is always possible, how about X + 1 (etc.)

• Subtask 1: 0 / 19
• Subtask 2: 0 / 25
• Subtask 3: 0 / 27
• Subtask 4: 0 / 29