Submission #791262

#TimeUsernameProblemLanguageResultExecution timeMemory
791262dungzDostavljač (COCI18_dostavljac)C++17
140 / 140
201 ms2500 KiB
// COCI 2017-2018 - Dostavljac // Lúcio Cardoso // Solution: // 1. Let dp[0][u][k] be the greatest amount we can achieve by starting our path at vertex u and // finishing it inside the subtree of u, using a cost k. Similarly, let dp[1][u][k] be the same as // the greatest amount in a path starting at u and ending at u with a cost of k. // 2. At first, dp[0][u][k] = dp[1][u][k] = A[k], for all k > 0. Then, we can use "knapsack on trees". // For each child v of u, we have: // * dp[0][u][k] = max(dp[0][u][k], max(dp[0][v][j], dp[1][v][j]) + dp[1][u][i-j-1]), for 0 <= j < k (we end our path inside the subtree of v) // * dp[0][u][k] = max(dp[0][u][k], dp[1][v][j] + dp[0][u][i-j-2]), for 0 <= j < k-1 (we end our path inside the subtree of another child) // * dp[1][u][k] = max(dp[1][u][k], dp[1][v][j] + dp[1][u][i-j-2]), for 0 <= j < k-1 (we can go through v's subtree) // 3. Final answer is max(dp[0][1][m], dp[1][1][m]). Overall complexity if O(n*m^2). #include <bits/stdc++.h> using namespace std; const int maxn = 510; int n, m; int A[maxn]; // 0 - ending inside subtree // 1 - coming back to vertex int dp[2][maxn][maxn]; vector<int> grafo[maxn]; void dfs(int u, int p) { for (int i = 1; i <= m; i++) dp[0][u][i] = dp[1][u][i] = A[u]; for (auto v: grafo[u]) { if (v == p) continue; dfs(v, u); for (int i = m; i >= 1; i--) { for (int j = 0; j <= i; j++) { if (i >= j+1) dp[0][u][i] = max(dp[0][u][i], max(dp[0][v][j], dp[1][v][j]) + dp[1][u][i-j-1]); if (i >= j+2) { dp[0][u][i] = max(dp[0][u][i], dp[1][v][j] + dp[0][u][i-j-2]); dp[1][u][i] = max(dp[1][u][i], dp[1][v][j] + dp[1][u][i-j-2]); } } } } } int main(void) { scanf("%d %d", &n, &m); for (int i = 1; i <= n; i++) scanf("%d", &A[i]); for (int i = 1; i < n; i++) { int u, v; scanf("%d %d", &u, &v); grafo[u].push_back(v); grafo[v].push_back(u); } dfs(1, 0); printf("%d\n", max(dp[0][1][m], dp[1][1][m])); }

Compilation message (stderr)

dostavljac.cpp: In function 'int main()':
dostavljac.cpp:63:7: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   63 |  scanf("%d %d", &n, &m);
      |  ~~~~~^~~~~~~~~~~~~~~~~
dostavljac.cpp:66:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   66 |   scanf("%d", &A[i]);
      |   ~~~~~^~~~~~~~~~~~~
dostavljac.cpp:71:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   71 |   scanf("%d %d", &u, &v);
      |   ~~~~~^~~~~~~~~~~~~~~~~
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