Submission #788883

#TimeUsernameProblemLanguageResultExecution timeMemory
788883vjudge1Bootfall (IZhO17_bootfall)C++17
65 / 100
878 ms4264 KiB
/* IN THE NAME OF GOD */ #include <bits/stdc++.h> // #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") using namespace std; typedef long long ll; typedef pair<ll, ll> pll; typedef pair<int, int> pii; typedef pair<int, pii> ipii; typedef pair<pii, int> piii; typedef pair<ll, pll> lpll; typedef pair<pll, ll> plll; typedef pair<pii, pii> piipii; typedef pair<pll, pll> pllpll; typedef long double ld; #define SQ 350 #define endl '\n' #define F first #define S second #define Mp make_pair #define pb push_back #define pf push_front #define PQ priority_queue #define size(x) ((ll)x.size()) #define all(x) (x).begin(),(x).end() #define kill(x) cout << x << '\n', exit(0); #define set_dec(x) cout << fixed << setprecision(x); #define ios ios_base::sync_with_stdio(false), cin.tie(0) #define fuck(x) cout << "(" << #x << " , " << x << ")" << endl #define file_io(x,y) freopen(x, "r", stdin); freopen(y, "w", stdout); const int N = 2e5+25, lg=18; int Mod = 5e8+10; //ll Mod = 998244353; ll max(ll a, ll b) {return (a>b ? a : b);} ll min(ll a, ll b) {return (a<b ? a : b);} ll abso(ll a) {return (a<0?-a:a);} inline int MOD(int a, int mod=Mod) { a += mod; while(a>=mod) a-=mod; return a; } inline ll poww(ll a, ll b) { ll ans = 1; a=MOD(a); while (b) { if (b & 1) ans = MOD(ans*a); b >>= 1; a = MOD(a*a); } return ans; } int n, A[505], dp[505*505], tmp[505*505], num[N], sum, z; int main () { //ios; cin>>n; for(int i=1; i<=n; i++) cin>>A[i], sum+=A[i]; for(int i=1; i<n; i++) if(MOD(A[i]%2, 2)!=MOD(A[i+1]%2, 2)) z = 1; if(z || MOD(sum%2, 2)==1) kill(0); dp[0] = 1; for(int i=1; i<=n; i++) { for(int j=sum; j>=A[i]; j--) { dp[j] = MOD(dp[j] + dp[j-A[i]]); } } for(int i=1; i<=n; i++) { for(int j=A[i]; j<=sum; j++) { tmp[j] = dp[j]; dp[j] = MOD(dp[j] - dp[j-A[i]]); } for(int f=MOD(A[1]%2, 2); f<=sum; f+=2) { if(dp[(f+sum-A[i])/2]>0) num[f]++; } for(int j=sum; j>=A[i]; j--) dp[j] = tmp[j]; } vector<ll> ans; for(int i=0; i<=sum; i++) { if(num[i]==n && dp[sum/2]>0) ans.pb(i); } cout<<size(ans)<<endl; for(auto i : ans) {cout<<i<<' ';} return 0; }
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