oj.uz

답안 #783489

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
783489 2023-07-15T01:39:19 Z PCTprobability Flood (IOI07_flood) C++17
100 / 100
 300 ms 27704 KB 
#include <bits/stdc++.h>
using namespace std;
#if __has_include(<atcoder/all>)
#include <atcoder/all>
using namespace atcoder;
#endif
using ll = int;
using ld = long double;
using ull = unsigned long long;
#define endl "\n"
typedef pair<int, int> Pii;
#define REP(i, n) for (int i = 0; i < (n); ++i)
#define REP3(i, m, n) for (int i = (m); (i) < int(n); ++ (i))
#define rep(i,a,b) for(int i=(int)(a);i<(int)(b);i++)
#define ALL(x) begin(x), end(x)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#define all(s) (s).begin(),(s).end()
#define drep2(i, m, n) for (int i = (m)-1; i >= (n); --i)
#define drep(i, n) drep2(i, n, 0)
#define rever(vec) reverse(vec.begin(), vec.end())
#define sor(vec) sort(vec.begin(), vec.end())
#define fi first
#define FOR_(n) for (ll _ = 0; (_) < (ll)(n); ++(_))
#define FOR(i, n) for (ll i = 0; (i) < (ll)(n); ++(i))
#define se second
#define pb push_back
#define P pair<ll,ll>
#define PQminll priority_queue<ll, vector<ll>, greater<ll>>
#define PQmaxll priority_queue<ll,vector<ll>,less<ll>>
#define PQminP priority_queue<P, vector<P>, greater<P>>
#define PQmaxP priority_queue<P,vector<P>,less<P>>
#define NP next_permutation
//const ll mod = 1000000009;
const ll mod = 998244353;
//const ll mod = 1000000007;
const ll inf = 4100000000000000000ll;
const ld eps = ld(0.00000000001);
static const long double pi = 3.141592653589793;
template<class T>void vcin(vector<T> &n){for(int i=0;i<int(n.size());i++) cin>>n[i];}
template<class T,class K>void vcin(vector<T> &n,vector<K> &m){for(int i=0;i<int(n.size());i++) cin>>n[i]>>m[i];}
template<class T>void vcout(vector<T> &n){for(int i=0;i<int(n.size());i++){cout<<n[i]<<" ";}cout<<endl;}
template<class T>void vcin(vector<vector<T>> &n){for(int i=0;i<int(n.size());i++){for(int j=0;j<int(n[i].size());j++){cin>>n[i][j];}}}
template<class T>void vcout(vector<vector<T>> &n){for(int i=0;i<int(n.size());i++){for(int j=0;j<int(n[i].size());j++){cout<<n[i][j]<<" ";}cout<<endl;}cout<<endl;}
void yes(bool a){cout<<(a?"yes":"no")<<endl;}
void YES(bool a){cout<<(a?"YES":"NO")<<endl;}
void Yes(bool a){cout<<(a?"Yes":"No")<<endl;}
void possible(bool a){ cout<<(a?"possible":"impossible")<<endl; }
void Possible(bool a){ cout<<(a?"Possible":"Impossible")<<endl; }
void POSSIBLE(bool a){ cout<<(a?"POSSIBLE":"IMPOSSIBLE")<<endl; }
#define FOR_R(i, n) for (ll i = (ll)(n)-1; (i) >= 0; --(i))
template<class T>auto min(const T& a){ return *min_element(all(a)); }
template<class T>auto max(const T& a){ return *max_element(all(a)); }
template<class T,class F>void print(pair<T,F> a){cout<<a.fi<<" "<<a.se<<endl;}
template<class T>bool chmax(T &a,const T b) { if (a<b) { a=b; return 1; } return 0;}
template<class T>bool chmin(T &a,const T b) { if (b<a) { a=b; return 1; } return 0;}
template<class T> void ifmin(T t,T u){if(t>u){cout<<-1<<endl;}else{cout<<t<<endl;}}
template<class T> void ifmax(T t,T u){if(t>u){cout<<-1<<endl;}else{cout<<t<<endl;}}
ll fastgcd(ll u,ll v){ll shl=0;while(u&&v&&u!=v){bool eu=!(u&1);bool ev=!(v&1);if(eu&&ev){++shl;u>>=1;v>>=1;}else if(eu&&!ev){u>>=1;}else if(!eu&&ev){v>>=1;}else if(u>=v){u=(u-v)>>1;}else{ll tmp=u;u=(v-u)>>1;v=tmp;}}return !u?v<<shl:u<<shl;}
ll modPow(ll a, ll n, ll mod) { if(mod==1) return 0;ll ret = 1; ll p = a % mod; while (n) { if (n & 1) ret = ret * p % mod; p = p * p % mod; n >>= 1; } return ret; }
vector<ll> divisor(ll x){ vector<ll> ans; for(ll i = 1; i * i <= x; i++){ if(x % i == 0) {ans.push_back(i); if(i*i!=x){ ans.push_back(x / ans[i]);}}}sor(ans); return ans; }
ll pop(ll x){return __builtin_popcountll(x);}
ll poplong(ll x){ll y=-1;while(x){x/=2;y++;}return y;}
P hyou(P a){ll x=fastgcd(abs(a.fi),abs(a.se));a.fi/=x;a.se/=x;if(a.se<0){a.fi*=-1;a.se*=-1;}return a;}
P Pplus(P a,P b){ return hyou({a.fi*b.se+b.fi*a.se,a.se*b.se});}
P Ptimes(P a,ll b){ return hyou({a.fi*b,a.se});}
P Ptimes(P a,P b){ return hyou({a.fi*b.fi,a.se*b.se});}
P Pminus(P a,P b){ return hyou({a.fi*b.se-b.fi*a.se,a.se*b.se});}
P Pgyaku(P a){ return hyou({a.se,a.fi});}
template<class T>
struct Sum{
  vector<T> data;
  Sum(const vector<T>& v):data(v.size()+1){
    for(ll i=0;i<v.size();i++) data[i+1]=data[i]+v[i];
  }
  T get(ll l,ll r) const {
    return data[r]-data[l];
  }
};
template<class T>
struct Sum2{
  vector<vector<T>> data;
  Sum2(const vector<vector<T>> &v):data(v.size()+1,vector<T>(v[0].size()+1)){
    for(int i=0;i<v.size();i++) for(int j=0;j<v[i].size();j++) data[i+1][j+1]=data[i][j+1]+v[i][j];
    for(int i=0;i<v.size();i++) for(int j=0;j<v[i].size();j++) data[i+1][j+1]+=data[i+1][j];
  }
  T get(ll x1,ll y1,ll x2,ll y2) const {
    return data[x2][y2]+data[x1][y1]-data[x1][y2]-data[x2][y1];
  }
};
 
void cincout(){
  ios::sync_with_stdio(false);
    std::cin.tie(nullptr);
  cout<< fixed << setprecision(15);
}
 
int main() {
  cincout();
  ll n;
  cin>>n;
  vector<ll> a(n),b(n);
  for(int i=0;i<n;i++) cin>>a[i]>>b[i];
  vector<ll> d(n);
  vector<vector<P>> g(n);
  map<P,ll> sp;
  for(auto &e:g){
    e.resize(4);
    for(auto &f:e) f={-1,-1};
  }
  ll m;
  cin>>m;
  vector<ll> p(m),q(m);
  vector<pair<P,P>> f(m);
  for(int i=0;i<m;i++){
    cin>>p[i]>>q[i];
    p[i]--;
    q[i]--;
    d[p[i]]++;
    d[q[i]]++;
    if(b[p[i]]==b[q[i]]){
      if(a[p[i]]<a[q[i]]){
        g[p[i]][0]={q[i],i};
        g[q[i]][2]={p[i],i};
        f[i].fi={p[i],0};
        f[i].se={q[i],2};
      }
      else{
        g[p[i]][2]={q[i],i};
        g[q[i]][0]={p[i],i};
        f[i].fi={p[i],2};
        f[i].se={q[i],0};
      }
    }
    else{
      if(b[p[i]]<b[q[i]]){
        g[p[i]][1]={q[i],i};
        g[q[i]][3]={p[i],i};
        f[i].fi={p[i],1};
        f[i].se={q[i],3};
      }
      else{
        g[p[i]][3]={q[i],i};
        g[q[i]][1]={p[i],i};
        f[i].fi={p[i],3};
        f[i].se={q[i],1};
      }
    }
  }
  multiset<P> ps;
  for(int i=0;i<n;i++) sp[{a[i],b[i]}]=i;
  for(int i=0;i<n;i++) if(d[i]) ps.insert({a[i],b[i]});
  vector<ll> ans;
  map<ll,ll> cnt;
  while(ps.size()){
    auto itr=ps.begin();
    int v=sp[*itr];
    int r=0;
    int u=v;
    vector<ll> ed;
    while(true){
      r++;
      r%=4;
      while(g[v][r].fi==-1){
        r+=3;
        r%=4;
      }
      if(cnt[g[v][r].se]==0) ed.pb(g[v][r].se);
      cnt[g[v][r].se]++;
      if(cnt[g[v][r].se]==2) ans.pb(g[v][r].se);
      int x=g[v][r].fi;
      g[v][r]={-1,-1};
      v=x;
      if(v==u) break;
    }
    for(auto e:ed){
      {
        auto E=f[e].fi;
        g[E.fi][E.se]={-1,-1};
        d[E.fi]--;
        if(d[E.fi]==0){
          ps.erase({a[E.fi],b[E.fi]});
        }
      }
      {
        auto E=f[e].se;
        g[E.fi][E.se]={-1,-1};
        d[E.fi]--;
        if(d[E.fi]==0){
          ps.erase({a[E.fi],b[E.fi]});
        }
      }
    }
  }
  sor(ans);
  cout<<ans.size()<<endl;
  for(auto e:ans) cout<<e+1<<endl;
}

Compilation message

flood.cpp:37:16: warning: overflow in conversion from 'long long int' to 'll' {aka 'int'} changes value from '4100000000000000000' to '-82182144' [-Woverflow]
   37 | const ll inf = 4100000000000000000ll;
      |                ^~~~~~~~~~~~~~~~~~~~~

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 0 ms 212 KB Output is correct

Subtask #3
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct

Subtask #4
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct

Subtask #5
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct

Subtask #6
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct

Subtask #7
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct

Subtask #8
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct

Subtask #9
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct

Subtask #10
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 30 ms 5452 KB Output is correct

Subtask #11
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 82 ms 19652 KB Output is correct

Subtask #12
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 89 ms 19716 KB Output is correct
2 Correct 300 ms 25444 KB Output is correct

Subtask #13
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 212 ms 23756 KB Output is correct
2 Correct 280 ms 25848 KB Output is correct

Subtask #14
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 241 ms 25236 KB Output is correct
2 Correct 232 ms 27704 KB Output is correct