Submission #781360

#TimeUsernameProblemLanguageResultExecution timeMemory
781360ZHIRDILBILDIZHedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++14
13 / 100
1006 ms186940 KiB
#include<bits/stdc++.h> using namespace std ; const int N = (1 << 20) ; map<int, int> sum ; int n, m, all_mn = 1e9, a[N + 1], ind[N + 1], pw[N + 1], mn1[N + 1][21], mn2[N + 1][21] ; void build_sparce_table1() { mn1[1][0] = a[1] ; for(int i = 2 ; i <= N ; i++) pw[i] = pw[i / 2] + 1, mn1[i][0] = a[i] ; for(int i = 1 ; i < 21 ; i++) for(int j = 1 ; j <= N - (1 << i) + 1 ; j++) mn1[j][i] = min(mn1[j][i - 1], mn1[j + (1 << (i - 1))][i - 1]) ; } int get_min1(int l, int r) { int num = pw[r - l + 1] ; return min(mn1[l][num], mn1[r - (1 << num) + 1][num]) ; } void build_sparce_table2() { mn2[1][0] = ind[1] ; for(int i = 2 ; i <= N ; i++) mn2[i][0] = ind[i] ; for(int i = 1 ; i < 21 ; i++) for(int j = 1 ; j <= N - (1 << i) + 1 ; j++) mn2[j][i] = min(mn2[j][i - 1], mn2[j + (1 << (i - 1))][i - 1]) ; } int get_min2(int l, int r) { int num = pw[r - l + 1] ; return min(mn2[l][num], mn2[r - (1 << num) + 1][num]) ; } signed main() { ios_base::sync_with_stdio( 0 ) ; cin.tie( 0 ) ; cout.tie( 0 ) ; cin >> n >> m ; for(int i = 1 ; i <= n ; i++) cin >> a[i], all_mn = min(all_mn, a[i]) ; if(n <= 500 && m <= 500) { int b[n + 1], c[n + 1] ; while(m--) { for(int i = 1 ; i <= n ; i++) b[i] = a[i], c[i] = a[i] ; int l, r, k, sum = 0 ; cin >> l >> r >> k ; sort(b + l, b + r + 1) ; for(int i = l ; i <= r ; i++) { int index = i ; for(int j = l ; j <= r ; j++) if(c[j] == b[i]){index = j ; break ;} for(int q = index ; q > i ; q--) swap(c[q], c[q - 1]), sum = max(sum, c[q] + c[q - 1]) ; } if(sum <= k)cout << "1\n" ; else cout << "0\n" ; } return 0 ; } if(n <= 5e3 && m <= 5e3) { return 0 ; } build_sparce_table1() ; for(int i = 1 ; i <= N ; i++) { int l = i, r = N + 1 ; while(l + 1 < r) { int mid = (l + r) >> 1 ; if(get_min1(i, mid) < a[i])r = mid ; else l = mid ; } ind[i] = r ; } build_sparce_table2() ; while(m--) { int l, r, k ; cin >> l >> r >> k ; if(l == r || get_min2(l, r - 1) > r)cout << "1\n" ; else cout << "0\n" ; } return 0 ; }
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