Submission #780655

#TimeUsernameProblemLanguageResultExecution timeMemory
780655CookieBitaro's travel (JOI23_travel)C++14
100 / 100
523 ms64320 KiB
#include<bits/stdc++.h> #include<fstream> using namespace std; ifstream fin("VNOICUP.INP"); ofstream fout("VNOICUP.OUT"); #define sz(a) (int)a.size() #define ll long long #define pb push_back #define forr(i, a, b) for(int i = a; i < b; i++) #define dorr(i, a, b) for(int i = a; i >= b; i--) #define ld long double #define vt vector #include<fstream> #define fi first #define se second #define pll pair<ll, ll> #define pii pair<int, int> const ld PI = 3.14159265359; using u128 = __uint128_t; //const int x[4] = {1, -1, 0, 0}; //const int y[4] = {0, 0, 1, -1}; const ll mod = 998244353; const int mxn = 2e5 + 5, mxq = 2e5 + 5, sq = 400, mxv = 2e7 + 5; //const int base = (1 << 18); const ll inf = 2e9 + 5, neg = -69420; int n; ll x[mxn + 1], mx[mxn + 1][18], mn[mxn + 1][18]; ll getmn(int l, int r){ int lg = __lg(r - l + 1); return(min(mn[l][lg], mn[r - (1 << lg) + 1][lg])); } ll getmx(int l, int r){ int lg = __lg(r - l + 1); return(max(mx[l][lg], mx[r - (1 << lg) + 1][lg])); } void solve(ll s){ int id = lower_bound(x, x + n + 1, s) - x; ll res, l, r; if(abs(x[id - 1] - s) <= abs(x[id] - s)){ res = abs(x[id - 1] - s); l = r = id - 1; }else{ l = r = id; res = x[id] - s; } bool turn = 1; while(l > 1 || r < n){ if(turn){ // go left int le = 1, ri = l - 1, ans = l; while(le <= ri){ int mid = (le + ri) >> 1; if(getmx(mid, l - 1) <= x[r + 1]){ ans = mid; ri = mid - 1; }else{ le = mid + 1; } } res += x[l] - x[ans]; if(r < n)res += x[++r] - x[ans]; l = ans; }else{ // go right int le = r + 1, ri = n, ans = r; while(le <= ri){ int mid = (le + ri) >> 1; if(getmn(r, mid - 1) > x[l - 1]){ ans = mid; le = mid + 1; }else{ ri = mid - 1; } } res += x[ans] - x[r]; if(l > 1)res += x[ans] - x[--l]; r = ans; } turn = !turn; } cout << res << "\n"; } signed main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> n; for(int i = 1; i <= n; i++){ cin >> x[i]; } x[0] = -inf; x[n + 1] = inf; for(int i = 0; i < n; i++){ mx[i][0] = 2 * x[i + 1] - x[i]; mn[i][0] = -x[i + 1] + 2 * x[i]; } for(int i = 1; i < 18; i++){ for(int j = 0; j + (1 << i) - 1 < n; j++){ mx[j][i] = max(mx[j][i - 1], mx[j + (1 << (i - 1))][i - 1]); mn[j][i] = min(mn[j][i - 1], mn[j + (1 << (i - 1))][i - 1]); } } int q; cin >> q; while(q--){ int s; cin >> s; solve(s); } return(0); }
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