Submission #779028

#TimeUsernameProblemLanguageResultExecution timeMemory
779028OrazBJust Long Neckties (JOI20_ho_t1)C++14
100 / 100
254 ms18576 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <functional> using namespace __gnu_pbds; using namespace std; typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; //Dijkstra->set //set.find_by_order(x) x-position value //set.order_of_key(x) number of strictly less elements don't need *set.?? #define N 100005 #define wr cout << "Continue debugging\n"; #define all(x) (x).begin(), (x).end() #define ll long long int #define pii pair <int, int> #define pb push_back #define ff first #define ss second map <int,int> cur; int main () { ios::sync_with_stdio(false); cin.tie(0); int n; cin >> n; vector<int> a(n+2), b(n+1), old_a(n+2); for (int i = 1; i <= n+1; i++) cin >> a[i], cur[a[i]] = 1e9+7, old_a[i] = a[i]; for (int i = 1; i <= n; i++) cin >> b[i]; sort(all(a)); sort(all(b)); vector<int> suff(n+3, 0); for (int i = n+1; i >= 1; i--){ suff[i] = max(suff[i+1], a[i]-b[i-1]); } int mx = 0; for (int i = 1; i <= n+1; i++){ cur[a[i]] = min(cur[a[i]], max(mx, suff[i+1])); mx = max(mx, a[i]-b[i]); } for (int i = 1; i <= n+1; i++) cout << cur[old_a[i]] << ' '; }
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