This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
//Dijkstra->set
//set.find_by_order(x) x-position value
//set.order_of_key(x) number of strictly less elements don't need *set.??
#define N 100005
#define wr cout << "Continue debugging\n";
#define all(x) (x).begin(), (x).end()
#define ll long long int
#define pii pair <int, int>
#define pb push_back
#define ff first
#define ss second
map <int,int> cur;
int main ()
{
ios::sync_with_stdio(false);
cin.tie(0);
int n;
cin >> n;
vector<int> a(n+2), b(n+1), old_a(n+2);
for (int i = 1; i <= n+1; i++) cin >> a[i], cur[a[i]] = 1e9+7, old_a[i] = a[i];
for (int i = 1; i <= n; i++) cin >> b[i];
sort(all(a)); sort(all(b));
vector<int> suff(n+3, 0);
for (int i = n+1; i >= 1; i--){
suff[i] = max(suff[i+1], a[i]-b[i-1]);
}
int mx = 0;
for (int i = 1; i <= n+1; i++){
cur[a[i]] = min(cur[a[i]], max(mx, suff[i+1]));
mx = max(mx, a[i]-b[i]);
}
for (int i = 1; i <= n+1; i++) cout << cur[old_a[i]] << ' ';
}
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