oj.uz

답안 #77901

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
77901 2018-10-01T06:27:25 Z Just_Solve_The_Problem 늑대인간 (IOI18_werewolf) C++11
34 / 100
 1138 ms 94760 KB 
#include <bits/stdc++.h>
#include "werewolf.h"
// #include "grader.cpp"

#define pb push_back
#define pii pair < int, int >
#define fr first
#define sc second
#define mk make_pair
#define okk puts("OK");

using namespace std;

const int smallN = (int)6e3 + 7;
const int N = (int)2e5 + 7;

int was[smallN];
int used[smallN];
vector < int > gr[N];
int l, r;
int n;
       
void dfs1(int v, int pr) {
	was[v]++;
	used[v] = 1;
	for (int to : gr[v]) {
		if (!used[to] && to >= l) dfs1(to, v);
	}
}

void dfs2(int v, int pr) {
	was[v]++;
	used[v] = 1;
	for (int to : gr[v]) {
		if (!used[to] && to <= r) dfs2(to, v);
	}
}  

vector < int > subtask12(int &N, vector < int > &X, vector < int > &Y, vector < int > &S, vector < int > &E, vector < int > &L, vector < int > &R) {
	n = N;
	for (int i = 0; i < (int)X.size(); i++) {
		gr[X[i]].pb(Y[i]);
		gr[Y[i]].pb(X[i]);
	}
	vector < int > ans;
	int q = S.size();
	for (int i = 0; i < q; i++) {
		l = L[i];
		r = R[i];
		memset(was, 0, sizeof was);
		dfs1(S[i], S[i]);
		memset(used, 0, sizeof used);
		dfs2(E[i], E[i]);
		memset(used, 0, sizeof used);
		int ok = 1;
		for (int j = l; j <= r; j++) {
			if (was[j] == 2) {
				ans.pb(1);
				ok = 0;
				break;
			}
		}
		if (ok) {
			ans.pb(0);
		}
	}
	return ans;
}

struct sparse {
	int table[2][20][N];
	/*
	0 = min
	1 = max
 	*/
 	sparse() { 		
 	}
	int numlog[N];
	void build(vector < int > &a) {
		numlog[0] = numlog[1] = 0;
		int nn = a.size();
		for (int i = 2; i < N; i++) {
			numlog[i] = numlog[i / 2] + 1;
		}
		for (int i = 0; i < 20; i++) {
			for (int j = 0; j < nn; j++) {
				if (i == 0) {
					table[0][i][j] = table[1][i][j] = a[j];
				} else {
					table[0][i][j] = min(table[0][i - 1][j], table[0][i - 1][min(j + (1 << (i - 1)), nn - 1)]);
					table[1][i][j] = max(table[1][i - 1][j], table[1][i - 1][min(j + (1 << (i - 1)), nn - 1)]);
				}
			}
		}
	}
	int getmax(int l, int r) {
		int lg = numlog[r - l + 1];
		return max(table[1][lg][l], table[1][lg][r - (1 << lg) + 1]);
	}
	int getmin(int l, int r) {
		int lg = numlog[r - l + 1];
		return min(table[0][lg][l], table[0][lg][r - (1 << lg) + 1]);
	}
};

vector < int > ar;
vector < int > pos;
sparse tb;

void dfs3(int v, int pr, int h = 0) {
	ar[h] = v;
	for (int to : gr[v]) {
		if (to != pr) {
			dfs3(to, v, h + 1);
		}
	}
}

pii getrange1(int v, int lim) {
	pii ret;
	ret = mk(v, v);
	int lo, hi;
	lo = 1; 
	hi = n + 1;
	while (hi - lo > 1) {
		int md = (lo + hi) >> 1;
		if (tb.getmin(max(0, v - md + 1), v) >= lim) {
			lo = md;
		} else {
			hi = md;
		}
	}
	ret.fr = max(0, v - lo + 1);
	lo = 1;
	hi = n + 1;
	while (hi - lo > 1) {
		int md = (lo + hi) >> 1;
		if (tb.getmin(v, min(v + md - 1, n - 1)) >= lim) {
			lo = md;
		} else {
			hi = md;
		}
	}
	ret.sc = min(v + lo - 1, n - 1);
	return ret;
}

pii getrange2(int v, int lim) {
	pii ret;
	ret = mk(v, v);
	int lo, hi;
	lo = 1; 
	hi = n + 1;
	while (hi - lo > 1) {
		int md = (lo + hi) >> 1;
		if (tb.getmax(max(0, v - md + 1), v) <= lim) {
			lo = md;
		} else {
			hi = md;
		}
	}
	ret.fr = max(0, v - lo + 1);
	lo = 1;
	hi = n + 1;
	while (hi - lo > 1) {
		int md = (lo + hi) >> 1;
		if (tb.getmax(v, min(v + md - 1, n - 1)) <= lim) {
			lo = md;
		} else {
			hi = md;
		}
	}
	ret.sc = min(v + lo - 1, n - 1);
	return ret;
}

vector < int > subtask3(int &N, vector < int > &X, vector < int > &Y, vector < int > &S, vector < int > &E, vector < int > &L, vector < int > &R) {
	n = N;
	int m = X.size();
	ar.resize(n);
	pos.resize(n);
	vector < int > ans;
	for (int i = 0; i < m; i++) {
		gr[X[i]].pb(Y[i]);
		gr[Y[i]].pb(X[i]);
	}
	for (int i = 0; i < n; i++) {
		if ((int)gr[i].size() == 1) {
			dfs3(i, i);
			break;
		}
	}         
	tb.build(ar);
	for (int i = 0; i < n; i++) {
		pos[ar[i]] = i;
	}
	int q = (int)S.size();
	ans.resize(q);
	for (int i = 0; i < q; i++) {
		int &res = ans[i];
		res = 0;
		pair < int, int > asd1 = getrange1(pos[S[i]], L[i]);
		pair < int, int > asd2 = getrange2(pos[E[i]], R[i]);
		if ((pos[S[i]] <= pos[E[i]] && asd1.sc >= asd2.fr) || (pos[E[i]] <= pos[S[i]] && asd2.sc >= asd1.fr)) {
			res = 1;
		}
	}  
	return ans;
}

struct DSU {
	int par[N];
	DSU() {
		iota(par, par + N, 0);
	}
	int getpar(int x) {
		return ((par[x] == x) ? x : getpar(par[x]));
	}
};
DSU dsu1, dsu2;

struct query {
	int id, t, x;
	query() {
	}
	query(int _id, int _t, int _x) {
		id = _id;
		t = _t;
		x = _x;
	}
};
vector < query > qq;

struct fen {
	int tree[N];
	fen() {
		memset(tree, 0, sizeof tree);
	}
	void upd(int pos) {
		while (pos < N) {
			tree[pos]++;
			pos = pos | (pos + 1);
		}
	}
	int get(int r) {
		int res = 0;
		while (r >= 0) {
			res += tree[r];
			r = (r & (r + 1)) - 1;
		}
		return res;
	}
};
fen tr;

vector < vector < int > > gr1, gr2;
int par[2][20][N];
int tiktak;
int tin[2][N], tout[2][N];
int pos1[N]; 

void dfs(vector < vector < int > > &GR, int id, int v, int pr) {
	par[id][0][v] = pr;
	for (int i = 1; i < 20; i++) {
		par[id][i][v] = par[id][i - 1][par[id][i - 1][v]];
	}
	tin[id][v] = ++tiktak;
	for (int to : GR[v]) {
		dfs(GR, id, to, v);
	}
	tout[id][v] = tiktak;
}

vector < int > subtask4(int &N, vector < int > &X, vector < int > &Y, vector < int > &S, vector < int > &E, vector < int > &L, vector < int > &R) {
	n = N;
	int m = X.size();
	int q = S.size();
	vector < int > ans;
	gr1.resize(n);
	gr2.resize(n);
	ans.resize(q);
	for (int i = 0; i < m; i++) {
		gr[X[i]].pb(Y[i]);
		gr[Y[i]].pb(X[i]);
	}                      
	for (int i = n - 1; i >= 0; i--) {
		for (int to : gr[i]) {
			if (i > to) continue;
			int x = dsu1.getpar(i);
			int y = dsu1.getpar(to);
			if (x == y) continue;
			dsu1.par[y] = x;
			gr1[x].pb(y);
		}
	}                       
	for (int i = 0; i < n; i++) {
		for (int to : gr[i]) {
			if (i < to) continue;
			int x = dsu2.getpar(i);
			int y = dsu2.getpar(to);
			if (x == y) continue;
			dsu2.par[y] = x;
			gr2[x].pb(y);
		}
	}                           
	dfs(gr1, 0, dsu1.getpar(0), dsu1.getpar(0));
	tiktak = 0;
	dfs(gr2, 1, dsu2.getpar(0), dsu2.getpar(0));
	for (int i = 0; i < q; i++) {
		int x = S[i];
		int y = E[i];
		int l = L[i];
		int r = R[i];               
		for (int j = 19; j >= 0; j--) { 
			if (par[0][j][x] >= l) x = par[0][j][x];
			if (par[1][j][y] <= r) y = par[1][j][y];
		}
		// cout << i << ' ' << x << ' ' << y << endl;
		qq.pb(query(~i, tin[0][x] - 1, y));
		qq.pb(query(i, tout[0][x], y));
	}
	sort(qq.begin(), qq.end(), [&](query &a, query &b) {
		return a.t < b.t;
	});
	// puts("***");
	for (int i = 0; i < n; i++) {
		pos1[tin[0][i] - 1] = tin[1][i];
	}
	int ord = 0;
	q = (int)qq.size();
	/*for (auto to : qq) {
		cout << to.id << ' ' << to.t << ' ' << to.x << '\n';
	} */
	for (int i = 0; i < q; i++) {
		while (ord < qq[i].t) tr.upd(pos1[ord++]);
		int delta = tr.get(tout[1][qq[i].x]) - tr.get(tin[1][qq[i].x] - 1);
		if (qq[i].id < 0) {
			ans[~qq[i].id] -= delta;
		} else {
			ans[qq[i].id] += delta;
		}
	}
	for (int i = 0; i < n; i++) {
		ans[i] = (ans[i] > 0);
	}
	return ans;                     
}


vector < int > check_validity(int N, vector < int > X, vector < int > Y, vector < int > S, vector < int > E, vector < int > L, vector < int > R) {
	return subtask4(N, X, Y, S, E, L, R);
	if (N <= 3000 && (int)X.size() <= 6000 && (int)S.size() <= 3000) {
		return subtask12(N, X, Y, S, E, L, R);
	} else if ((int)X.size() == N - 1) {
		return subtask3(N, X, Y, S, E, L, R);
	} 
	return subtask4(N, X, Y, S, E, L, R);
}

Subtask #1
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 8 ms 7672 KB Output is correct
2 Correct 8 ms 7672 KB Output is correct
3 Incorrect 8 ms 7752 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #2
0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 8 ms 7672 KB Output is correct
2 Correct 8 ms 7672 KB Output is correct
3 Incorrect 8 ms 7752 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #3
34.0 / 34.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1138 ms 82572 KB Output is correct
2 Correct 937 ms 88472 KB Output is correct
3 Correct 856 ms 88472 KB Output is correct
4 Correct 893 ms 88472 KB Output is correct
5 Correct 929 ms 88472 KB Output is correct
6 Correct 989 ms 88472 KB Output is correct
7 Correct 1027 ms 88472 KB Output is correct
8 Correct 753 ms 88592 KB Output is correct
9 Correct 604 ms 88592 KB Output is correct
10 Correct 538 ms 88592 KB Output is correct
11 Correct 573 ms 88592 KB Output is correct
12 Correct 582 ms 88592 KB Output is correct
13 Correct 920 ms 94740 KB Output is correct
14 Correct 923 ms 94760 KB Output is correct
15 Correct 980 ms 94760 KB Output is correct
16 Correct 873 ms 94760 KB Output is correct
17 Correct 1045 ms 94760 KB Output is correct

Subtask #4
0 / 51.0

# 결과 실행 시간 메모리 Grader output
1 Correct 8 ms 7672 KB Output is correct
2 Correct 8 ms 7672 KB Output is correct
3 Incorrect 8 ms 7752 KB Output isn't correct
4 Halted 0 ms 0 KB -